如何访问Ratchet WebSockets中的Guzzle QueryString参数？

Question

嗨,我正在使用radchet websocket.我很难从对象变量中获取数据.

请检查我的代码:

var conn = new WebSocket('ws://localhost:8080?user_id=10&receiver_id=20');
$querystring = $conn->WebSocket->request->getQuery();
print_r($querystring);

输出:

Guzzle\Http\QueryString Object
(
    [fieldSeparator:protected] => &
    [valueSeparator:protected] => =
    [urlEncode:protected] => RFC 3986
    [aggregator:protected] =>
    [data:protected] => Array
        (
            [user_id] => 10
            [receiver_id] => 20
        )
)

上面的代码我想user_id和receiver_id,但我无法得到.

我的代码:

echo $querystring->data:protected['user_id'];
echo $querystring->data:protected['receiver_id'];

我已经回应但收到错误消息.请帮我.

编辑:

如果我将对象转换为数组,则表示格式不正确.见下文.

$array =  (array)  $querystring;
print_r($array);

输出:

Array
(
    [ * fieldSeparator] => &
    [ * valueSeparator] => =
    [ * urlEncode] => RFC 3986
    [ * aggregator] =>
    [ * data] => Array
        (
            [user_id] => 10
            [receiver_id] => 20
        )

)

Answer 1

Guzzle\Http\QueryString扩展了Guzzle\Common\Collection,因此您应该能够使用Collection的方法:

$user_id = $querystring->get('user_id');
$receiver_id = $querystring->get('receiver_id');

要么

$parameters = $querystring->toArray();
$user_id = $parameters['user_id'];
$receiver_id = $parameters['receiver_id'];