Select2 - Ajax数据 - 根据查询填充下拉列表

Stu*_*ett 0 php jquery codeigniter jquery-select2

我正在使用Select2来填充英国城镇的下拉列表.由于英国城镇数据库庞大,我认为AJAX调用将是引入数据的最佳方式.

我已经构建了一个post函数和一些PHP(在Codeigniter中)来捕获查询并解析它.

我可以看到数据正在发布和响应,但我的Select2没有填充数据.

我的jQuery是这样的:

 $("#areas").select2(
    {
        tags: [],
        ajax: {
            url: '/profile/get-towns',
            dataType: 'json',
            type: "POST",
            quietMillis: 100,
            data: function (term) {
                return {
                    query: term
                };
            },
            results: function (data) {
                return {
                    results: data.town_id
                }
            },
            cache: true
        },
        escapeMarkup: function (markup) { return markup; }, // let our custom formatter work
        minimumInputLength: 4,
        placeholder         : "Start typing your Town / City",
        maximumSelectionSize: 2
    }
);
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我的回复jSON(示例)如下:

[{"town_id":"16994","town":"Hartle"},{"town_id":"16995","town":"Hartlebury"},{"town_id":"16996","town"
:"Hartlebury"},{"town_id":"16997","town":"Hartlebury Common"},{"town_id":"16998","town":"Hartlepool"
},{"town_id":"16999","town":"Hartley"},{"town_id":"17000","town":"Hartley"},{"town_id":"17001","town"
:"Hartley"},{"town_id":"17002","town":"Hartley"},{"town_id":"17003","town":"Hartley Green"},{"town_id"
:"17004","town":"Hartley Green"},{"town_id":"17005","town":"Hartley Mauditt"},{"town_id":"17006","town"
:"Hartley Wespall"},{"town_id":"17007","town":"Hartley Wintney"},{"town_id":"27051","town":"New Hartley"
},{"town_id":"35891","town":"Stowe-by-Chartley"}]
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我哪里错了?理想情况下,我希望选择下拉列表的选择值= town_id,并选择选项作为城镇名称.

谢谢.

Luc*_*one 5

在您的select2配置中:

results: function (data) {
    var res = [];
    for(var i  = 0 ; i < data.length; i++) {
        res.push({id:data[i].town_id, text:data[i].town});
    }
    return {
        results: res
    }
},
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becasue select2希望结果作为对象的阵列的键idtext.

否则你可能已经返回一个格式良好的对象

[
   {"id":"16994","text":"Hartle"},
   {"id":"16995","text":"Hartlebury"},
   {"id":"16996","text":"Hartlebury"},
   {"id":"16997","text":"Hartlebury Common"}
]
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然后

results: function (data) {
    return {
        results: data
    }
},
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  • 我只想注意,在4.0.0中我们将`results`重命名为`processResults`,但同样的想法仍然适用(你需要`id`和`text`键). (2认同)