Joh*_*hal 10 mysql subquery sql-view sql-update
嗨我有这样的表:
表格条目:
id | total_comments
_____________________
1 | 0
2 | 0
3 | 0
4 | 0
表评论:
id | 开斋节 评论
_____________________
1 | 1 | 评论sdfd
2 | 1 | 测试测试
3 | 1 | 评论文本
4 | 2 | 虚拟评论
5 | 2 | 样本评论
6 | 1 | fg fgh dfh
我写的查询:
UPDATE entry
SET total_comments = total_comments + 1
WHERE id IN ( SELECT eid
FROM comments
WHERE id IN (1,2,3,4,5,6))
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我得到的结果是:
表格条目:
id | total_comments
_____________________
1 | 1
2 | 1
3 | 0
4 | 0
Expected results :
table entry :
id | total_comments
_____________________
1 | 4
2 | 2
3 | 0
4 | 0
Any help will be appreciated.
OMG*_*ies 19
使用:
UPDATE entry
SET total_comments = (SELECT COUNT(*)
FROM COMMENTS c
WHERE c.eid = id
GROUP BY c.eid)
WHERE id IN ( SELECT eid
FROM comments
WHERE id IN (1,2,3,4,5,6))
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