两个日期之间的小时数列表

Question

我想创建一个以小时为增量的日期列表，如下所示：

['2012060100', '2012060101', '2012060102', '2012060103', '2012060104', '2012060105', '2012060106', '2012060107', '2012060108', '2012060109', '2012060110', '2012060111', '2012060112', '2012060113', '2012060114', '2012060115', '2012060116', '2012060117', '2012060118', '2012060119', '2012060120', '2012060121', '2012060122', '2012060123', '2012060200', '2012060201', '2012060202'... '2012083122', '2012083123']

我正在尝试这样的事情：

deb = '20120601'
fin = '20120831'

start = datetime.datetime.strptime(deb, "%Y%m%d")
end = datetime.datetime.strptime(fin, "%Y%m%d")

date_lst = [start + datetime.timedelta(days=x) for x in range(0, ((end-start).days)+1)]

date_list = [dt.strftime("%Y%m%d") for dt in date_lst]

但它仅打印之间的日期列表start和end这样的：

['20120601', '20120602', '20120603', '20120604', ... , '20120830', '20120831']

Answer 1

如果需要小时，则需要包含'%H'在格式字符串中。如果您添加timedelta以天为单位的 s，您也不会获得小时数。

from datetime import datetime as dt, timedelta

deb = '20120601'
fin = '20120831'

start = dt.strptime(deb, "%Y%m%d")
end = dt.strptime(fin, "%Y%m%d") + timedelta(days=1)

def hour_range(start, end):
    while start < end:
        yield start
        start += timedelta(hours=1)

date_list = [h.strftime('%Y%m%d%H') for h in hour_range(start, end)]