Ruby:从阵列中的多个赋值中丢弃变量

Question

对于从数组给定的变量赋值:

a,b,c,d,e = [ "foo","bar","discard","discard","blah" ]

有没有办法只a,b以及e分配和丢弃c和d？undef在perl中是否有类似的东西(Perl赋值使用虚拟占位符).

Answer 1

是.

a,b,_,_,e = [ "foo","bar","discard","discard","blah" ]

`_`不会导致有关未使用变量的警告(在启用警告时运行;`ruby -w`) (2认同)
@PressingOnAlways:Ruby专门处理[`_`变量(以及Ruby 2.0中具有前导下划线的任何其他变量)(http://stackoverflow.com/a/9560198/479863)这个. (2认同)

Answer 2

您可以使用splat运算符.

 a,b,*,e = ["foo","bar",nil,nil,"blah"]