use*_*366 5 c++ inheritance templates iterator
快速询问下面实现迭代器的最佳方法是什么:
假设我有一个模板化的基类'List'和两个子类"ListImpl1"和"ListImpl2".基类的基本要求是可迭代的,即我可以这样做:
for(List<T>::iterator it = list->begin(); it != list->end(); it++){
...
}
Run Code Online (Sandbox Code Playgroud)
我也想允许迭代器添加,例如:
for(List<T>::iterator it = list->begin()+5; it != list->end(); it++){
...
}
Run Code Online (Sandbox Code Playgroud)
所以问题是ListImpl1的迭代器的实现将与ListImpl2的迭代器的实现不同.我通过使用包含指向ListIteratorImpl的指针的包装器ListIterator来解决这个问题,该指针包含子类ListIteratorImpl2和ListIteratorImpl2,但它们都变得非常混乱,特别是当您需要在ListIterator中实现operator +时.
有没有想过更好的设计来解决这些问题?
如果您可以使List<T>::iterator非虚拟化,那么将虚拟化委派给List会使事情变得简单:
template<typename T>
class List
{
virtual void add_assign(iterator& left, int right) = 0;
public:
class iterator
{
const List* list;
const T* item;
public:
iterator(const List* list, const T* item) : list(list), item(item) {}
iterator& operator +=(int right)
{
list->add_assign(*this, right);
return *this;
}
static iterator operator +(iterator const& left, int right)
{
iterator result = left;
result += right;
return result;
}
};
virtual iterator begin() const = 0;
virtual iterator end() const = 0;
};
Run Code Online (Sandbox Code Playgroud)
否则(例如,如果迭代器需要存储明显不同的数据),那么您必须执行常规的,无聊的指针实现以获得虚拟性:
template<typename T>
class List
{
class ItImpl
{
virtual ItImpl* clone() = 0;
virtual void increment() = 0;
virtual void add(int right) = 0;
};
public:
class iterator
{
ItImpl* impl;
public:
// Boring memory management stuff.
iterator() : impl() {}
iterator(ItImpl* impl) : impl(impl) {}
iterator(iterator const& right) : impl(right.impl->clone()) {}
~iterator() { delete impl; }
iterator& operator=(iterator const& right)
{
delete impl;
impl = right.impl->clone();
return *this;
}
// forward operators to virtual calls through impl.
iterator& operator+=(int right)
{
impl->add(right);
return *this;
}
iterator& operator++()
{
impl->increment();
return *this;
}
};
};
template<typename T>
static List<T>::iterator operator+(List<T>::iterator const& left, int right)
{
List<T>::iterator result = left;
result += right;
return result;
}
template<typename T>
class MagicList : public List<T>
{
class MagicItImpl : public ItImpl
{
const MagicList* list;
const magic* the_magic;
// implement ...
};
public:
iterator begin() const { return iterator(new MagicItImpl(this, begin_magic)); }
iterator end() const { return iterator(new MagicItImpl(this, end_magic)); }
};
Run Code Online (Sandbox Code Playgroud)