我正在尝试低估如何在C++中使用结构作为列表.我提出了一段代码,对我来说,这不应该导致任何错误,但它确实......
我的代码是这样的:
struct item {
int data;
struct item *next;
};
struct item *begin = NULL;
void add(int x) {
struct item *a = new struct item();
a->data = x;
a->next = begin;
begin = a;
}
int main() {
add(2);
printf("%d\n", begin->data);
return 0;
}
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它给了我这个:
Undefined symbols for architecture x86_64:
"operator new(unsigned long)", referenced from:
add(int) in structtest-f49486.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
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我在我的mac终端中使用GCC来运行我的代码.我之前没有见过这种类型的错误.我发现删除该行时错误不存在
struct item *a = new struct item();
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谁能告诉我这里有什么问题?
谢谢,
Merijn
使用g++不gcc.看起来它试图将您的C++代码链接为C代码.
海湾合作委员会很奇怪.当您使用g++到链接,它静静地增加了C++支持库,如定义默认的一个operator new.
是的,它"忘记"它只是将代码编译为C++.不要问我为什么.
关于clang和gcc,这是我在Mac上看到的:
$ gcc --version
gcc (MacPorts gcc48 4.8.4_0) 4.8.4
Copyright (C) 2013 Free Software Foundation, Inc.
This is free software; see the source for copying conditions. There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
$ type -a gcc
gcc is /opt/local/bin/gcc
gcc is /usr/bin/gcc
$ /usr/bin/gcc --version
Configured with: --prefix=/Applications/Xcode.app/Contents/Developer/usr --with-gxx-include-dir=/usr/include/c++/4.2.1
Apple LLVM version 6.1.0 (clang-602.0.49) (based on LLVM 3.6.0svn)
Target: x86_64-apple-darwin14.3.0
Thread model: posix
$ ls -lF /usr/bin/gcc
-rwxr-xr-x 1 root wheel 14160 Sep 29 2014 /usr/bin/gcc*
$ ls -lF /usr/bin/g++
-rwxr-xr-x 1 root wheel 14160 Sep 29 2014 /usr/bin/g++*
$ file /usr/bin/gcc
/usr/bin/gcc: Mach-O 64-bit executable x86_64
$ file /usr/bin/g++
/usr/bin/g++: Mach-O 64-bit executable x86_64
$ diff /usr/bin/g++ /usr/bin/gcc
Binary files /usr/bin/g++ and /usr/bin/gcc differ
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请注意,我安装了MacPorts,通过它安装了真正的GCC 4.8,并将其配置为"替换"Apple的"gcc".顺便说一句,Apple gcc不是符号链接.