jQuery.validator.addMethod中的.post总是返回false

Question

我是jQuery和javascript编程的新手.我有一个程序,检查用户名是否被采用.目前,PHP脚本始终返回

  if(isset($_POST["username"]) )//&& isset($_POST["checking"]))
    {
        $xml="<register><message>Available</message></register>";
        echo $xml;
    }

登录功能有效,但用户名检查不起作用.有任何想法吗？这是我的所有代码:

$(document).ready(function() {
jQuery.validator.addMethod("checkAvailability",function(value,element){
    $.post( "login.php" , {username:"test", checking:"yes"}, function(xml){
        if($("message", xml).text() == "Available") return true;
        else return false;
    });
},"Sorry, this user name is not available");
$("#loginForm").validate({
    rules:  {
        username: {
            required: true,
            minlength: 4,
            checkAvailability: true
        },
        password:{
            required: true,
            minlength: 5
        }
    },
    messages: {
        username:{
            required: "You need to enter a username." ,
            minlength: jQuery.format("Your username should be at least {0} characters long.")
        }
    },
    highlight: function(element, errorClass) {
                $(element).fadeOut("fast",function() {
                $(element).fadeIn("slow");
                })
    },
    success: function(x){
        x.text("OK!")
    },
    submitHandler: function(form){send()}
});
function send(){
    $("#message").hide("fast");
    $.post( "login.php" , {username:$("#username").val(), password:$("#password").val()}, function(xml){
        $("#message").html( $("message", xml).text() );
        if($("message", xml).text() == "You are successfully logged in.")
        {
            $("#message").css({ "color": "green" });
            $("#message").fadeIn("slow", function(){location.reload(true);});
        }
        else
        {
            $("#message").css({ "color": "red" });
            $("#message").fadeIn("slow");
        }
    });
}
$("#newUser").click(function(){

    return false;
});

});

Answer 1

没关系,现在正在工作.这是代码:

$(document).ready(function() {
jQuery.validator.addMethod("checkAvailability",function(value,element){
 var x= $.ajax({
    url: "login.php",
    type: 'POST',
    async: false,
    data: "username=" + value + "&checking=true",
 }).responseText;
 if($("message", x).text()=="true") return true;
 else return false;
},"Sorry, this user name is not available");
$("#loginForm").validate({
    rules:  {
        username: {
            required: true,
            minlength: 4,
            checkAvailability: true
        },
        password:{
            required: true,
            minlength: 5
        }
    },
    messages: {
        username:{
            required: "You need to enter a username." ,
            minlength: jQuery.format("Your username should be at least {0} characters long.")
        }
    },
    highlight: function(element, errorClass) {
                $(element).fadeOut("fast",function() {
                $(element).fadeIn("slow");
                })
    },
    success: function(x){
        x.text("OK!")
    },
    submitHandler: function(form){send()}
});
function send(){
    $("#message").hide("fast");
    $.post( "login.php" , {username:$("#username").val(), password:$("#password").val()}, function(xml){
        $("#message").html( $("message", xml).text() );
        if($("message", xml).text() == "You are successfully logged in.")
        {
            $("#message").css({ "color": "green" });
            $("#message").fadeIn("slow", function(){location.reload(true);});
        }
        else
        {
            $("#message").css({ "color": "red" });
            $("#message").fadeIn("slow");
        }
    });
}
$("#newUser").click(function(){

    return false;
});
});

Answer 2

您需要使用扩展的形式$.post()是$.ajax()这样你就可以在设置async选项设置为false,如下所示:

jQuery.validator.addMethod("checkAvailability",function(value,element){
    $.ajax({
      url: "login.php",
      type: 'POST',
      async: false,
      data: {username:"test", checking:"yes"},
      success: function(xml) {
        return $("message", xml).text() == "Available";
      }
    });
},"Sorry, this user name is not available");

目前,您的success分析响应的函数在验证结束后发生,因为它是异步操作.所以目前,在使用返回值时它并没有返回任何东西,并且undefined〜= false,这就是它总是显得错误的原因.通过设置async为false,您可以在没有回调的情况下按顺序执行代码,因此实际使用上面示例中的返回.

另一种选择,如果你可以调整你的页面的返回结构是使用验证插件的内置remote选项,这只是为了这种事情:)