ResultSet丢失第一个值

Question

代码似乎工作正常,但我注意到每当我查询只有一个结果的字符串时,它什么也没有返回.不知怎的,我正在跳过我想的第一个结果,但不知道为什么.

    else{
   Conn con = null;
   try {
    con = new Conn();
   } catch (Exception e) {

    e.printStackTrace();
   }
   String sql = "SELECT productname, quantityperunit, unitprice FROM products pr, categories ca WHERE pr.categoryID = ca.categoryID AND ProductName LIKE '%" + searchTerm + "%'";
   System.out.println("last try");
   try {
    searchResults = con.query(sql);

    if (searchResults.next()){
     session.setAttribute("searchResults", searchResults);
    }


   } catch (Exception e) {

    e.printStackTrace();
   } 


  }

这是显示代码:

 java.sql.ResultSet resultSet = (java.sql.ResultSet) session.getAttribute("searchResults");
    if(resultSet == null){
     out.println("Nullified");
    }
 if(resultSet!=null){
  out.println("<table border='1'>");
     out.println("<tr><th>Product Name</th><th>Quantity per Item</th><th>Price</th><th>Quantity</th><th><Add to Cart</th></tr>");
     while(resultSet.next()){      
      out.println("<tr><td>"+resultSet.getString("ProductName")+"</td></tr>");
     }
     out.println("</table>");
 }

任何帮助,将不胜感激.

Answer 1

改变这个:

searchResults = con.query(sql);
if (searchResults.next()){
    session.setAttribute("searchResults", searchResults);
}

对此:

while(resultSet.next()) {
   out.println(""+resultSet.getString("ProductName")+""); } out.println(""); 
}