如果我只有少数子列表元素,如何从列表中删除整个子列表？蟒蛇

Question

我正在尝试从列表中删除子列表并获取此错误:ValueError:list.remove(x):x not in list

我希望删除子列表,尽管x只有少数来自子字符串的元素

类似的东西:

list_a=[[1,2,3],[4,5,6]]

list_a.remove([1,3])

list_a

[4,5,6]

---

来自以下评论:

我有产品清单:

products=[['0001', 'Hummus', 'Food', 'ISR', '10-04-2015'], ['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

lst[0],lst[2]并且lst[3]每种产品都是独一无二的.我希望删除整个子列表,通过这三个元素,如:

>>> products.remove(['0001', 'Food', 'ISR'])
>>> products
['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']

.

def del_product(depot, product_data):
'''
    del_product
    delets a validated product data from the depot
    if such a product does not exist in the depot
    then no action is taken

    arguments:
    depot - list of lists
    product_data - list

    return value: boolean
'''

# Your code goes her

if validate_product_data(product_data)==True:
    for product in depot:
        if equal_products(product, product_data)==True:
            rem = set(product_data)
            for x in reversed(depot):
                if rem.issubset(x):
                    depot.remove(x)

            return True
        else:
            continue
    return False

Answer 1

您可以检查是否[1,3] 是set.issubset的子集:

list_a = [[1,2,3],[4,5,6]]

rem = set([1,3])

list_a[:] = [ x for x in list_a if not rem.issubset(x)]
print(list_a)

s.issubset(t)s <= t测试s中的每个元素是否都在t中

使用list_a[:]更改原始列表.

与您的产品列表完全相同:

products=[['0001', 'Hummus', 'Food', 'ISR', '10-04-2015'], ['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

rem = set(['0001', 'Food', 'ISR'])

products[:] = [ x for x in products if not rem.issubset(x)]
print(products)
[['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

使用循环,如果它更容易遵循,你可以组合反转和issubset:

products=[['0001', 'Hummus', 'Food', 'ISR', '10-04-2015'], ['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

rem = set(['0001', 'Food', 'ISR'])   

for x in reversed(products):
    if rem.issubset(x):
        products.remove(x)
print(products)