调用requestLocationUpdates()时,不能将活动用作LocationListener的实例

Dan*_*ñez 2 android localization android-studio location-services

在我的应用程序中,在连接到LocationServices.API之后,在onConnected()回调中,我启动了一个位置Updates Request,问题是处理进程的Activity(DataActivity)无法识别为LocationListener的一个实例,它显示了一个错误,并建议投射.

protected void startLocationUpdates() {
    PendingResult locationUpdatesResult = LocationServices.FusedLocationApi.requestLocationUpdates(locationGoogleApiClient, locationRequest, (com.google.android.gms.location.LocationListener) this);
}
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当我将最后一个参数转换为(com.google.android.gms.location.LocationListener)时,IDE允许我编译,但抛出ClassCastException

java.lang.ClassCastException:com.example.[...].无法将数据活动强制转换为com.google.android.gms.location.LocationListener

我真的不知道为什么会这样.

这是班级宣言.

public class DataActivity extends FragmentActivity implements LocationListener, ConnectionCallbacks , OnConnectionFailedListener, OnMapReadyCallback{
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OnCreate():

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_data);

    //Create the GoogleLocationAPI reference
    buildGoogleLocationApiClient();

    //Create Location Request
    createLocationRequest();

    //Initialize the mapFragment
    initializeMapFragment();

    updateUI();
}
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其他方法:

protected synchronized void buildGoogleLocationApiClient(){
    locationGoogleApiClient = new GoogleApiClient.Builder(this)
            .addApi(LocationServices.API)
            .addConnectionCallbacks(this)
            .addOnConnectionFailedListener(this)
            .build();
    locationGoogleApiClient.connect();
    Log.v("**INFO: ", "API CLIENT");
}

protected static void createLocationRequest() {
    locationRequest = new LocationRequest();
    locationRequest.setPriority(LocationRequest.PRIORITY_HIGH_ACCURACY);
    locationRequest.setInterval(10000);
    locationRequest.setFastestInterval(5000);
    Log.i("**INFO: ", "LocationRequest created");
}

protected void initializeMapFragment(){
    //Initialize the mapFragment
    mapFragment = (MapFragment) getFragmentManager().findFragmentById(R.id.map);
    //When mapFragment is ready...
    mapFragment.getMapAsync(this);
}
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因此,当建立连接(OnConnected)时,我会在错误弹出时调用此方法.

protected void startLocationUpdates() {
    PendingResult locationUpdatesResult = LocationServices.FusedLocationApi.requestLocationUpdates(locationGoogleApiClient, locationRequest, this);
    locationUpdatesResult.await(); 
}
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Ger*_*ero 16

确保你的DataActivity工具,com.google.android.gms.location.LocationListener而不是android.location.LocationListener.
您可能android.location.LocationListener错误地导入了.