c ++/cli将(托管)委托传递给非托管代码

Question

如何将函数指针从托管C++(C++/CLI)传递给非托管方法？我读了一些文章,比如MSDN中的这篇文章,但它描述了两个不同的程序集,而我只想要一个.

这是我的代码:

1)标题(MyInterop.ManagedCppLib.h):

#pragma once

using namespace System;

namespace MyInterop { namespace ManagedCppLib {

    public ref class MyManagedClass
    {
    public:
        void DoSomething();
    };
}}

2)CPP代码(MyInterop.ManagedCppLib.cpp)

#include "stdafx.h"
#include "MyInterop.ManagedCppLib.h"

#pragma unmanaged
void UnmanagedMethod(int a, int b, void (*sum)(const int))
{
    int result = a + b;
    sum(result);
}

#pragma managed
void MyInterop::ManagedCppLib::MyManagedClass::DoSomething()
{
    System::Console::WriteLine("hello from managed C++");
    UnmanagedMethod(3, 7, /* ANY IDEA??? */);
}

我尝试创建我的托管委托,然后我尝试使用Marshal::GetFunctionPointerForDelegate方法,但我无法编译.

Answer 1

是的,你想要Marshal :: GetFunctionPointerForDelegate().您的代码段缺少您想要调用的托管函数,我只是编写了一个.您还必须声明托管委托类型并在获取函数指针之前创建它的实例.这很好用:

#include "stdafx.h"

using namespace System;
using namespace System::Runtime::InteropServices;

#pragma managed(push, off)
typedef void (* UnmanagedSummer)(int arg);

void UnmanagedMethod(int a, int b, UnmanagedSummer sum)
{
    int result = a + b;
    sum(result);
}
#pragma managed(pop)

ref class Test {
    delegate void ManagedSummer(int arg);
public:
    static void Run() {
        Test^ t = gcnew Test();
        ManagedSummer^ managed = gcnew ManagedSummer(t, &Sum);
        IntPtr stubPointer = Marshal::GetFunctionPointerForDelegate(managed);
        UnmanagedSummer functionPointer = static_cast<UnmanagedSummer>(stubPointer.ToPointer());
        UnmanagedMethod(1, 2, functionPointer);
        GC::KeepAlive(managed);    // Important: ensure stub can't be collected while native code is running
        System::Diagnostics::Debug::Assert(t->summed == 3);
    }
    void Sum(int arg) {
        summed += arg;
    }
    int summed;
};

int main(array<System::String ^> ^args)
{
    Test::Run();
    return 0;
}