Ras*_*ari 3 c# serialization json json.net
我将这个简单的代码编写为Serialize类为flatten,但是当我使用[JsonConverter(typeof(FJson))]注释时,它会抛出StackOverflowException.如果我SerializeObject手动调用它,它工作正常.
如何在注释模式下使用JsonConvert:
class Program
{
static void Main(string[] args)
{
A a = new A();
a.id = 1;
a.b.name = "value";
string json = null;
// json = JsonConvert.SerializeObject(a, new FJson()); without [JsonConverter(typeof(FJson))] annotation workd fine
// json = JsonConvert.SerializeObject(a); StackOverflowException
Console.WriteLine(json);
Console.ReadLine();
}
}
//[JsonConverter(typeof(FJson))] StackOverflowException
public class A
{
public A()
{
this.b = new B();
}
public int id { get; set; }
public string name { get; set; }
public B b { get; set; }
}
public class B
{
public string name { get; set; }
}
public class FJson : JsonConverter
{
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
JToken t = JToken.FromObject(value);
if (t.Type != JTokenType.Object)
{
t.WriteTo(writer);
return;
}
JObject o = (JObject)t;
writer.WriteStartObject();
WriteJson(writer, o);
writer.WriteEndObject();
}
private void WriteJson(JsonWriter writer, JObject value)
{
foreach (var p in value.Properties())
{
if (p.Value is JObject)
WriteJson(writer, (JObject)p.Value);
else
p.WriteTo(writer);
}
}
public override object ReadJson(JsonReader reader, Type objectType,
object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
public override bool CanConvert(Type objectType)
{
return true; // works for any type
}
}
Json.NET没有方便的支持转换器调用JToken.FromObject生成"默认"序列化,然后修改结果JToken输出 - 正是因为StackOverflowException你观察到的将发生.
一种解决方法是使用线程静态布尔值在递归调用中临时禁用转换器.使用线程静态是因为在某些情况下(包括asp.net-web-api),JSON转换器的实例将在线程之间共享.在这种情况下,通过实例属性禁用转换器将不是线程安全的.
public class FJson : JsonConverter
{
[ThreadStatic]
static bool disabled;
// Disables the converter in a thread-safe manner.
bool Disabled { get { return disabled; } set { disabled = value; } }
public override bool CanWrite { get { return !Disabled; } }
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
JToken t;
using (new PushValue<bool>(true, () => Disabled, (canWrite) => Disabled = canWrite))
{
t = JToken.FromObject(value, serializer);
}
if (t.Type != JTokenType.Object)
{
t.WriteTo(writer);
return;
}
JObject o = (JObject)t;
writer.WriteStartObject();
WriteJson(writer, o);
writer.WriteEndObject();
}
private void WriteJson(JsonWriter writer, JObject value)
{
foreach (var p in value.Properties())
{
if (p.Value is JObject)
WriteJson(writer, (JObject)p.Value);
else
p.WriteTo(writer);
}
}
public override object ReadJson(JsonReader reader, Type objectType,
object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
public override bool CanConvert(Type objectType)
{
return true; // works for any type
}
}
public struct PushValue<T> : IDisposable
{
Action<T> setValue;
T oldValue;
public PushValue(T value, Func<T> getValue, Action<T> setValue)
{
if (getValue == null || setValue == null)
throw new ArgumentNullException();
this.setValue = setValue;
this.oldValue = getValue();
setValue(value);
}
#region IDisposable Members
// By using a disposable struct we avoid the overhead of allocating and freeing an instance of a finalizable class.
public void Dispose()
{
if (setValue != null)
setValue(oldValue);
}
#endregion
}
注意这个转换器只写; 阅读没有实现.
顺便提一下,您编写的转换器会创建具有重复名称的JSON:
Run Code Online (Sandbox Code Playgroud)[JsonConverter(typeof(FJson))] public class A { }
这虽然不是严格违法,但通常被认为是不好的做法
如果您确定不会跨线程共享转换器,则可以使用成员变量:
public static partial class JsonExtensions
{
public static JToken DefaultFromObject(this JsonSerializer serializer, object value)
{
if (value == null)
return JValue.CreateNull();
var dto = Activator.CreateInstance(typeof(DefaultSerializationDTO<>).MakeGenericType(value.GetType()), value);
var root = JObject.FromObject(dto, serializer);
return root["Value"].RemoveFromLowestPossibleParent() ?? JValue.CreateNull();
}
public static object DefaultToObject(this JToken token, Type type, JsonSerializer serializer = null)
{
var oldParent = token.Parent;
var dtoToken = new JObject(new JProperty("Value", token));
var dtoType = typeof(DefaultSerializationDTO<>).MakeGenericType(type);
var dto = (IHasValue)(serializer ?? JsonSerializer.CreateDefault()).Deserialize(dtoToken.CreateReader(), dtoType);
if (oldParent == null)
token.RemoveFromLowestPossibleParent();
return dto == null ? null : dto.GetValue();
}
public static JToken RemoveFromLowestPossibleParent(this JToken node)
{
if (node == null)
return null;
// If the parent is a JProperty, remove that instead of the token itself.
var contained = node.Parent is JProperty ? node.Parent : node;
contained.Remove();
// Also detach the node from its immediate containing property -- Remove() does not do this even though it seems like it should
if (contained is JProperty)
((JProperty)node.Parent).Value = null;
return node;
}
interface IHasValue
{
object GetValue();
}
[JsonObject(NamingStrategyType = typeof(DefaultNamingStrategy), IsReference = false)]
class DefaultSerializationDTO<T> : IHasValue
{
public DefaultSerializationDTO(T value) { this.Value = value; }
public DefaultSerializationDTO() { }
[JsonConverter(typeof(NoConverter)), JsonProperty(ReferenceLoopHandling = ReferenceLoopHandling.Serialize)]
public T Value { get; set; }
object IHasValue.GetValue() { return Value; }
}
}
public class NoConverter : JsonConverter
{
// NoConverter taken from this answer https://stackoverflow.com/a/39739105/3744182
// To https://stackoverflow.com/questions/39738714/selectively-use-default-json-converter
// By https://stackoverflow.com/users/3744182/dbc
public override bool CanConvert(Type objectType) { throw new NotImplementedException(); /* This converter should only be applied via attributes */ }
public override bool CanRead { get { return false; } }
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer) { throw new NotImplementedException(); }
public override bool CanWrite { get { return false; } }
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) { throw new NotImplementedException(); }
}
在此方案中,必须调用JsonConverter.WriteJson()并传递传入的串行器,以便[JsonConverter(typeof(FJson))]使用转换器的相同实例.完成此操作后,您可以将其恢复A到您的班级JsonConverter:
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
JToken t = serializer.DefaultFromObject(value);
// Remainder as before
if (t.Type != JTokenType.Object)
{
t.WriteTo(writer);
return;
}
JObject o = (JObject)t;
writer.WriteStartObject();
WriteJson(writer, o);
writer.WriteEndObject();
}
小智 6
我还不能发表评论，对此感到抱歉...但我只是想在 Paul Kiar 提供的解决方案中添加一些内容。他的解决方案确实帮助了我。
Paul 的代码很短并且简单地工作，无需任何自定义的对象构建。我想要做的唯一补充是插入一个检查，如果该属性被忽略。如果将其设置为忽略，则跳过该属性的写入：
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
JsonObjectContract contract = (JsonObjectContract)serializer.ContractResolver.ResolveContract(value.GetType());
writer.WriteStartObject();
foreach (var property in contract.Properties)
{
if (property.Ignored)
continue;
writer.WritePropertyName(property.PropertyName);
writer.WriteValue(property.ValueProvider.GetValue(value));
}
writer.WriteEndObject();
}
在阅读(和测试)Paul Kiar和p.kaneman解决方案后,我会说这似乎是一项具有挑战性的任务WriteJson.即使它适用于大多数情况 - 有一些尚未涵盖的边缘情况.例子:
public bool ShouldSerialize*() 方法null 值struct)这是(只是)另一个尝试:
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) {
if (ReferenceEquals(value, null)) {
writer.WriteNull();
return;
}
var contract = (JsonObjectContract)serializer
.ContractResolver
.ResolveContract(value.GetType());
writer.WriteStartObject();
foreach (var property in contract.Properties) {
if (property.Ignored) continue;
if (!ShouldSerialize(property, value)) continue;
var property_name = property.PropertyName;
var property_value = property.ValueProvider.GetValue(value);
writer.WritePropertyName(property_name);
if (property.Converter != null && property.Converter.CanWrite) {
property.Converter.WriteJson(writer, property_value, serializer);
} else {
serializer.Serialize(writer, property_value);
}
}
writer.WriteEndObject();
}
private static bool ShouldSerialize(JsonProperty property, object instance) {
return property.ShouldSerialize == null
|| property.ShouldSerialize(instance);
}
小智 5
我不喜欢上面发布的解决方案，所以我弄清楚了序列化程序实际上是如何序列化对象的，并试图将其提取到最小：
public override void WriteJson( JsonWriter writer, object value, JsonSerializer serializer )
{
JsonObjectContract contract = (JsonObjectContract)serializer.ContractResolver.ResolveContract( value.GetType() );
writer.WriteStartObject();
foreach ( var property in contract.Properties )
{
writer.WritePropertyName( property.PropertyName );
writer.WriteValue( property.ValueProvider.GetValue(value));
}
writer.WriteEndObject();
}
没有堆栈溢出问题，也不需要递归禁用标志。