tableView outlet nil在加载表时

Ryg*_*uyu 1 uitableview ios swift

我有一个tabBarController和两个UINavigationControllersUITableViews连接到tabBarController.我有子类,tabBarController所以我可以通过引用传递两个表之间的自定义对象数组.但是,当我去填充数组时,tableView插座将展开为nil并且我收到错误"致命错误:在解开可选值时意外地发现nil".不知道为什么会这样.以下是代码:

tabBarController

protocol CustomTabBarDelegate {
var placeDataArray : Array <placeData> {get set}
}

class placeData: Equatable {
var description : String
var selected : Bool

init (description : String, selected : Bool) {
    self.description = description
    self.selected = selected
}
}

class PlacesTabBarController: UITabBarController {

var placeDataArray = Array<placeData>()

override func viewDidLoad() {
    super.viewDidLoad()

    placeDataArray = [placeData(description: "Afghanistan", selected: false), placeData(description: "Albania", selected: false)]

    var table1 = AllPlacesViewController()
    var table2 = AttendingPlacesTableViewController()

    table1.delegate = self
    table2.delegate = self

    var navController1 = UINavigationController(rootViewController: table1)
    var navController2 = UINavigationController(rootViewController: table2)

    self.viewControllers = [navController1, navController2]
    }
}
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tableViewControllers

var delegate:PlacesTabBarController!
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然后,例如,我可以通过调用访问该数组

delegate.placeDataArray.count
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当我去填表时

@IBOutlet weak var allPlacesTableView: UITableView!
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并使用

 var cell = self.allPlacesTableView.dequeueReusableCellWithIdentifier("Cell") as UITableViewCell
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抛出上面提到的错误.不知道为什么allPlacesTableView打包到零

pba*_*sdf 6

当您像这样创建VC时,

var table1 = AllPlacesViewController()
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它们没有与故事板相关联,因此没有实现出口.使用instantiateViewControllerWithIdentifierself.storyboard 的方法:

var table1 : AllPlacesViewController = UIStoryboard(name: "Main", bundle: nil).instantiateViewControllerWithIdentifier("AllPlaces") as AllPlacesViewController
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