Gre*_*n23 2 arrays bash pointers associative-array
是否有一种方法Bash,使一个指针的值的关键在一个关联数组?像这样:
declare -A mapp
mapp=( ["key"]="${value}" )
for k in "${!mapp[@]}"; do
pointer="${mapp["${k}"]}" # How do I do this?
done
Run Code Online (Sandbox Code Playgroud)
通常,您不需要使用指针,但我很想知道是否有办法制作指针.
在更简单的情况下(即,对于普通/字符串变量),我会做一个像这样的指针:
pointer=b
read -p "Enter something: " b
eval pointer=\$${pointer}
Run Code Online (Sandbox Code Playgroud)
我如何为关联数组执行此操作?这不起作用(跳过strikethroughed代码):
declare -A mapp
mapp=( ["first"]="${a}" ["second"]="${b}" )
for k in "${!mapp[@]}"; do
v=mapp["${k}"]
read -p "Enter ${k}: " new
eval v=\$${v} # Doesn't work
done
Run Code Online (Sandbox Code Playgroud)
declare -A mapp
mapp=( ["first"]="${a}" ["second"]="${b}" )
for k in "${!mapp[@]}"; do
v=mapp["${k}"]
read -p "Enter ${k}: " k
eval v=\$${v} # Doesn't work
done
Run Code Online (Sandbox Code Playgroud)
这也不起作用(跳过strikethroughed代码):
declare -A mapp
mapp=( ["first"]="${a}" ["second"]="${b}" )
for k in "${!mapp[@]}"; do
v=mapp
read -p "Enter ${k}: " new
eval v=\$${v["${k}"]} # Doesn't work (and has terrible readability)
done
Run Code Online (Sandbox Code Playgroud)
declare -A mapp
mapp=( ["first"]="${a}" ["second"]="${b}" )
for k in "${!mapp[@]}"; do
v=mapp
read -p "Enter ${k}: " k
eval v=\$${v["${k}"]} # Doesn't work (and has terrible readability)
done
Run Code Online (Sandbox Code Playgroud)
在bash4.3中,您可以使用nameref:
$ mapp=([key]=value)
$ declare -n x=mapp[key] # NO dollar sign!
$ x=7
$ echo ${mapp[key]}
7
Run Code Online (Sandbox Code Playgroud)
在4.3之前,您需要以declare不同方式使用该命令来执行间接操作.
$ mapp=([key]=value)
$ x=mapp[key] # NO dollar sign!
$ declare "$x=7"
$ echo ${mapp[key]}
7
Run Code Online (Sandbox Code Playgroud)