我有一个由单词组成的字符串,其中一些包含标点符号,我想删除它,但我一直无法弄清楚如何执行此操作.
例如,如果我有类似的东西
var words = "Hello, this : is .. a string?"
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我希望能够创建一个数组
"[Hello, this, is, a, string]"
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我最初的想法是使用类似的东西words.stringByTrimmingCharactersInSet()
删除我不想要的任何字符,但这只会使字符脱离结束.
我想也许我可以用一些东西来迭代字符串
for letter in words {
if NSCharacterSet.punctuationCharacterSet.characterIsMember(letter){
//remove that character from the string
}
}
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但我不确定如何从字符串中删除字符.我确信if语句的设置方式也存在一些问题,但它显示了我的思考过程.
Leo*_*bus 21
Xcode 8.3.2•Swift 3.1
extension StringProtocol {
var words: [SubSequence] {
return split{ !$0.isLetter }
}
}
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let sentence = "Hello, this : is .. a string?"
let words = sentence.words // ["Hello", "this", "is", "a", "string"]
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String
有一种enumerateSubstringsInRange()
方法。使用该.ByWords
选项,它会自动检测单词边界和标点符号:
迅捷3/4:
let string = "Hello, this : is .. a \"string\"!"
var words : [String] = []
string.enumerateSubstrings(in: string.startIndex..<string.endIndex,
options: .byWords) {
(substring, _, _, _) -> () in
words.append(substring!)
}
print(words) // [Hello, this, is, a, string]
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斯威夫特2:
let string = "Hello, this : is .. a \"string\"!"
var words : [String] = []
string.enumerateSubstringsInRange(string.characters.indices,
options: .ByWords) {
(substring, _, _, _) -> () in
words.append(substring!)
}
print(words) // [Hello, this, is, a, string]
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这适用于 Xcode 8.1、Swift 3:
首先定义用于过滤的通用扩展CharacterSet
:
extension String {
func removingCharacters(inCharacterSet forbiddenCharacters:CharacterSet) -> String
{
var filteredString = self
while true {
if let forbiddenCharRange = filteredString.rangeOfCharacter(from: forbiddenCharacters) {
filteredString.removeSubrange(forbiddenCharRange)
}
else {
break
}
}
return filteredString
}
}
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然后使用标点符号过滤:
let s:String = "Hello, world!"
s.removingCharacters(inCharacterSet: CharacterSet.punctuationCharacters) // => "Hello world"
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