CakePHP 3级深度模型关联

Nao*_*den 2 php children cakephp join paginate

我对CakePHP比较陌生,我对文档做得很好,但我一直试图找到解决这个问题的方法好几周,我似乎没有找到解决方案,我相信这很容易也许甚至可以自动化,但我只是不知道如何找到它(也许我不知道这些事情的行话)

我的模型结构是这样的:

<?php
    class Trip extends AppModel {
          var $belongsTo = array(
            'User' => array(
                'className' => 'User',
                'foreignKey' => 'user_id'
            ),
            'Start' => array(
                'className' => 'Place',
                'foreignKey' => 'start_id'
            ),
            'End' => array(
                'className' => 'Place',
                'foreignKey' => 'end_id'
            ),
            'Transport' => array(
                'className' => 'Transport',
                'foreignKey' => 'transport_id'
            )
        );

     }
?>

<?php
class Place extends AppModel {

    var $belongsTo = array(
        'User' => array(
            'className' => 'User',
            'foreignKey' => 'user_id'
        ),
        'Country' => array(
            'className' => 'Country',
            'foreignKey' => 'country_id'
        ),
        'State' => array(
            'className' => 'State',
            'foreignKey' => 'state_id'
        ),
        'City' => array(
            'className' => 'City',
            'foreignKey' => 'city_id'
        )
    );
    var $hasMany = array(
        'PlaceStart' => array(
            'className' => 'trip',
            'foreignKey' => 'start_id',
            'dependent' => false
        ),
        'PlaceEnd' => array(
            'className' => 'trip',
            'foreignKey' => 'end_id',
            'dependent' => false
        )
    );

}
?>

<?php
class State extends AppModel {

    var $belongsTo = array(
        'Country' => array(
            'className' => 'Country',
            'foreignKey' => 'country_id',
            'conditions' => '',
            'fields' => '',
            'order' => ''
        )
    );

    var $hasMany = array(
        'City' => array(
            'className' => 'City',
            'foreignKey' => 'city_id',
            'dependent' => false
        )
    );

}
?>
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...等等用户,城市,国家和运输模型.

我想要实现的是在搜索a时获取整棵树的所有信息Trip.

<?php
class TripController extends AppController {
    function index() {
        debug($this->Trip->find('first'));
    }
}
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输出

Array
(
    [Trip] => Array
        (
            [id] => 6
            [created] => 2010-05-04 00:23:59
            [user_id] => 4
            [start_id] => 2
            [end_id] => 1
            [title] => My trip
            [transport_id] => 1
        )

    [User] => Array
        (
            [id] => 4
            [name] => John Doe
            [email] => john.doe@mailinator.com
        )

    [Start] => Array
        (
            [id] => 2
            [user_id] => 4
            [country_id] => 1
            [state_id] => 1
            [city_id] => 1
            [direccion] => Lincoln Street
        )

    [End] => Array
        (
            [id] => 1
            [user_id] => 4
            [country_id] => 1
            [state_id] => 1
            [city_id] => 4
            [address] => Fifth Avenue
        )

    [Transport] => Array
        (
            [id] => 1
            [name] => car
        )
)
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这是一个问题: 如何从树中获取所有信息?

我想有类似的东西

Array
(
    [Trip] => Array
        (
            [id] => 6
            [created] => 2010-05-04 00:23:59
            [User] => Array
                (
                    [id] => 4
                    [name] => John Doe
                    [email] => john.doe@mailinator.com
                )
            [Start] => Array
                (
                    [id] => 2
                    [user_id] => 4
                    [Country] => Array
                        (
                            [id] => 1
                            [name] = Spain
                        )
                    [State] => Array
                        (
                            [id] => 1
                            [name] = Barcelona
                        )
                    [City] => Array
                        (
                            [id] => 1
                            [name] = La Floresta
                        )
                    [address] => Lincoln Street
                )
            [End] => (same as Start)
            [title] => My trip
            [Transport] => Array
                (
                    [id] => 1
                    [name] => car
                )
        )
)
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CakePHP可以创建这种数据吗?不仅是因为,$this->Model->find()而且$this->paginate()例如:

    // filter by start
    if(isset($this->passedArgs['start'])) {
        //debug('isset '.$this->passedArgs['start']);
        $start = $this->passedArgs['start'];
        $this->paginate['conditions'][] = array(
            'OR' => array(
                'Start.address LIKE' => "%$start%",
                'Start.State.name LIKE' => "%$start%",
                'Start.City.name LIKE' => "%$start%",
                'Start.Country.name LIKE' => "%$start%"
            )
        );
        $this->data['Search']['start'] = $start;
    }
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这似乎是一个粗略的问题,但我确信这是广泛完成和记录,我真的很感激任何帮助.

pau*_*llb 6

你好像设置好了.您应该做的就是将递归设置为2,这样可以为您的数据提供额外的级别(假设您已正确设置了所有关系)

var $recursive =2;
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