typescript扩展了一个不需要的接口

Question

我有两个接口;

interface ISuccessResponse {
    Success: boolean;
    Message: string;
}

和

interface IAppVersion extends ISuccessResponse {
    OSVersionStatus: number;
    LatestVersion: string;
}

我想将ISuccessResponse接口扩展为Not Required; 我可以覆盖它,但还有其他选择吗？

interface IAppVersion {
    OSVersionStatus: number;
    LatestVersion: string;
    Success?: boolean;
    Message?: string;
}

我不想这样做.

Answer 1

有点晚了,但是Typescript 2.1引入了Partial<T>允许你要求的类型:

interface ISuccessResponse {
    Success: boolean;
    Message: string;
}

interface IAppVersion extends Partial<ISuccessResponse> {
    OSVersionStatus: number;
    LatestVersion: string;
}

declare const version: IAppVersion;
version.Message // Type is string | undefined

Answer 2

如果需要Success并且Message是可选的，可以执行以下操作：

interface IAppVersion {
    OSVersionStatus: number;
    LatestVersion: string;
    Success?: boolean;
    Message?: string;
}

您不能使用extends关键字来引入ISuccessResponse接口，而是要更改在该接口中定义的合同（该接口表明它们是必需的）。

Answer 3

从 TypeScript 3.5 开始，您可以使用Omit：

interface IAppVersion extends Omit<ISuccessResponse, 'Success' | 'Message'> {
  OSVersionStatus: number;
  LatestVersion: string;
  Success?: boolean;
  Message?: string;
}