如何使用python(版本2.5)压缩文件夹的内容？

Question

一旦我在特定文件夹中拥有了我需要的所有文件,我希望我的python脚本压缩文件夹内容.

这可能吗？

我怎么能这样做呢？

Answer 1

在python 2.7上你可以使用:shutil.make_archive(base_name,format [,root_dir [,base_dir [,verbose [,dry_run [,owner [,group [,logger]]]]]]]).

base_name存档名称减去扩展名

存档的格式格式

要压缩的root_dir目录.

例如

 shutil.make_archive(target_file, format="bztar", root_dir=compress_me)    

Answer 2

脚本的改编版本是:

#!/usr/bin/env python
from __future__ import with_statement
from contextlib import closing
from zipfile import ZipFile, ZIP_DEFLATED
import os

def zipdir(basedir, archivename):
    assert os.path.isdir(basedir)
    with closing(ZipFile(archivename, "w", ZIP_DEFLATED)) as z:
        for root, dirs, files in os.walk(basedir):
            #NOTE: ignore empty directories
            for fn in files:
                absfn = os.path.join(root, fn)
                zfn = absfn[len(basedir)+len(os.sep):] #XXX: relative path
                z.write(absfn, zfn)

if __name__ == '__main__':
    import sys
    basedir = sys.argv[1]
    archivename = sys.argv[2]
    zipdir(basedir, archivename)

例:

C:\zipdir> python -mzipdir c:\tmp\test test.zip

它'C:\zipdir\test.zip'使用'c:\tmp\test'目录的内容创建存档.

Answer 3

这是一个递归版本

def zipfolder(path, relname, archive):
    paths = os.listdir(path)
    for p in paths:
        p1 = os.path.join(path, p) 
        p2 = os.path.join(relname, p)
        if os.path.isdir(p1): 
            zipfolder(p1, p2, archive)
        else:
            archive.write(p1, p2) 

def create_zip(path, relname, archname):
    archive = zipfile.ZipFile(archname, "w", zipfile.ZIP_DEFLATED)
    if os.path.isdir(path):
        zipfolder(path, relname, archive)
    else:
        archive.write(path, relname)
    archive.close()