与Picasso的ShareActionProvider分享图片

Question

我花了几个小时才找到这个解决方案......

所以我决定分享这个信息,也许有一个它会有用:)

第一种方法(如下所示)从视图中获取位图并将其加载到文件中.

// Get access to ImageView 
ImageView ivImage = (ImageView) findViewById(R.id.ivResult);
// Fire async request to load image
Picasso.with(context).load(imageUrl).into(ivImage);

然后假设在图像完成加载后,这就是你可以触发共享的方式:

// Can be triggered by a view event such as a button press
public void onShareItem(View v) {
    // Get access to bitmap image from view
    ImageView ivImage = (ImageView) findViewById(R.id.ivResult);
    // Get access to the URI for the bitmap
    Uri bmpUri = getLocalBitmapUri(ivImage);
    if (bmpUri != null) {
        // Construct a ShareIntent with link to image
        Intent shareIntent = new Intent();
        shareIntent.setAction(Intent.ACTION_SEND);
        shareIntent.putExtra(Intent.EXTRA_STREAM, bmpUri);
        shareIntent.setType("image/*");
        // Launch sharing dialog for image
        startActivity(Intent.createChooser(shareIntent, "Share Image"));    
    } else {
        // ...sharing failed, handle error
    }
}

// Returns the URI path to the Bitmap displayed in specified ImageView
public Uri getLocalBitmapUri(ImageView imageView) {
    // Extract Bitmap from ImageView drawable
    Drawable drawable = imageView.getDrawable();
    Bitmap bmp = null;
    if (drawable instanceof BitmapDrawable){
       bmp = ((BitmapDrawable) imageView.getDrawable()).getBitmap();
    } else {
       return null;
    }
    // Store image to default external storage directory
    Uri bmpUri = null;
    try {
        File file =  new File(Environment.getExternalStoragePublicDirectory(  
            Environment.DIRECTORY_DOWNLOADS), "share_image_" + System.currentTimeMillis() + ".png");
        file.getParentFile().mkdirs();
        FileOutputStream out = new FileOutputStream(file);
        bmp.compress(Bitmap.CompressFormat.PNG, 90, out);
        out.close();
        bmpUri = Uri.fromFile(file);
    } catch (IOException e) {
        e.printStackTrace();
    }
    return bmpUri;
}

确保为AndroidManifest.xml添加适当的权限:

<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"/>
<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" />

Answer 1

共享图像的第二种方法不需要您将图像写入文件。可以在UI线程上安全地执行此代码。此方法已在此网页http://www.nurne.com/2012/07/android-how-to-attach-image-file-from.html上建议。

ImageView siv = (ImageView) findViewById(R.id.ivResult);
Drawable mDrawable = siv.getDrawable();
Bitmap mBitmap = ((BitmapDrawable)mDrawable).getBitmap();

String path = Images.Media.insertImage(getContentResolver(), 
    mBitmap, "Image Description", null);

Uri uri = Uri.parse(path);
return uri;

您从ImageView获得Drawable。您从Drawable获得位图。将该位图放入媒体图像存储中。这为您提供了一个可以代替文件路径或URL的路径。请注意，原始网页还有一个不变的位图的问题，可以通过将位图绘制到画布中来解决（屏幕上从未显示）。有关详细信息，请参见上面的链接页面。