Isa*_*ein 7 excel vba function excel-vba
我正在使用一个函数,它允许我查看一串文本并评估它是否由字母组成.它位于一个名为"General"的模块中.通用模块仅用于容纳公共函数和变量.功能代码如下:
Public Function IsAlpha(strValue As String) As Boolean
Dim intPos As Integer
For intPos = 1 To Len(strValue)
Select Case Asc(Mid(strValue, intPos, 1))
Case 65 To 90, 97 To 122
IsLetter = True
Case Else
IsLetter = False
Exit For
End Select
Next
End Function
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接下来,我有两个"if"例程,用于评估userform中文本框的前2个字符.第一个例程询问第一个字符是否为数字,第二个例程询问第二个字符是否为alpha.目前,当IsAlpha测试为True时,第二个"if"例程将我从子例程中弹出,而不是生成MsgBox.是否正确调用IsAlpha函数?
如果下面列出了例程代码:
Private Sub CmdMap_Click()
With TxtDxCode
If IsNumeric(Left(Me.TxtDxCode.Text, 1)) Then
MsgBox "Incorrect DX Code format was entered. ", vbExclamation, "DX Code Entry"
TxtDxCode.Value = ""
TxtDxCode.SetFocus
Exit Sub
End If
If IsAlpha(Left(Me.TxtDxCode.Text, 2)) Then
MsgBox "Incorrect DX Code format was entered. ", vbExclamation, "DX Code Entry"
TxtDxCode.Value = ""
TxtDxCode.SetFocus
Exit Sub
End If
End With
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Sam*_*Sam 11
为什么不使用正则表达式呢?然后没有涉及的循环:
Public Function IsAlpha(strValue As String) As Boolean
IsAlpha = strValue Like WorksheetFunction.Rept("[a-zA-Z]", Len(strValue))
End Function
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此外,当您创建用户定义函数(UDF)时,您需要确保将返回值分配给实际函数的名称,在这种情况下IsAlpha- IsLetter否则该值将永远不会被传回.
检查字符串是否仅包含字母字符的最直接、简洁且高效的方法是使用以下函数:
Function IsAlpha(s) As Boolean
IsAlpha = Len(s) And Not s Like "*[!a-zA-Z]*"
End Function
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事实上,这稍微好一点......
Function IsAlpha(s$) As Boolean
IsAlpha = Not s Like "*[!a-zA-Z]*"
End Function
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尝试这个IsAlpha
Public Function IsAlpha(strValue As String) As Boolean
Dim intPos As Integer
For intPos = 1 To Len(strValue)
Select Case Asc(Mid(strValue, intPos, 1))
Case 65 To 90, 97 To 122
IsAlpha = True
Case Else
IsAlpha = False
Exit For
End Select
Next
End Function
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