如何在jsDoc中建立方法参数类型的链接

uza*_*y95 5 jsdoc

是否有任何自然方式或特殊标记使参数类型成为链接? 在此输入图像描述

/**
* My js app
* @module app
*/
/** 
* Namespace for MYAPP classes and functions.
* @namespace HUMAN_RESOURCE
*/
var HUMAN_RESOURCE = HUMAN_RESOURCE || {};

/**
* @class JustClass
* @constructor
*/
HUMAN_RESOURCE.JustClass = function(){ }

/**
* Constructs Person objects
* @class Person
* @constructor
* @param {String} First name
* @param {String} Last name
*/
HUMAN_RESOURCE.Person = function (first, last) {    
    /**
    * First name of the Person
    * @property first_name
    * @type String
    */
    this.first_name = first;

    /**
    * @property f_createPerson
    * @param {Person} [_person] aç?klama
    * @return {Person} Person type object
    */
    this.f_createPerson = function(_person, _person2){ return new Person() }
};

/**
* Return Person's full name
* @alias getName
* @memberof! HUMAN_RESOURCE.Person#
* @return {String} First name + last name
*/
HUMAN_RESOURCE.Person.prototype.getName = function () {
    return this.first_name + ' ' + this.last_name;
};
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SGD*_*SGD 6

幸运的是,正确的名称路径并不总是显而易见(但您基本上可以在生成的文档的顶部看到它)

/**
* @property f_createPerson
* @param {module:app~HUMAN_RESOURCE.Person} [_person] aç?klama
* @return {module:app~HUMAN_RESOURCE.Person} Person type object
*/
this.f_createPerson = function(_person, _person2){ return new Person() }
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  • JSdoc3 的另一个需要简化的特性。` (@link MyModule#aMethod}` (2认同)