如何在while循环中只显示一次

Question

我有一个运行的mysql查询,它检查迭代器是否等于1,然后显示这个div标题...

if ($this->dliterator == 1) {echo "<div class='clientsection' id='downloads'>Downloads</div><br/>";};

问题是,dl迭代器可能不一定从1开始(它与数据库中的downloadid直接相关).

我怎样才能得到这个只在第一次循环显示ONLY？

while ($row = mysql_fetch_assoc($result)) { 

   if ($row['download'] != null){
    if ($this->dliterator == 1) {echo "<div class='clientsection' id='downloads'>Downloads</div><br/>";};


    if ($editDownload == 1) {
     echo "<div class='clientlink' style='margin-top: 15px;'>";
     echo "<input name='downloads[$this->dliterator][name]' type='text' id='download$this->dliterator' value='" . $row['download'] . "'/>";
     echo "<input name='downloads[$this->dliterator][title]' type='text' id='downloadtitle$this->dliterator' value='" . $row['downloadtitle'] . "'/>";
     echo "<img class='removelink' src='/images/deletelink.png' width='15' />";
     echo "<input id='downloadid' name='downloads[$this->dliterator][id]' type='hidden' value='".$row['downloadid']."' style='display: none'/>";
     echo "<br/><img id='uploaddownload$uploaditerator' class='uploaddownload' src='../images/upload.png' width='80'/>"; 
     echo "</div>";


    };

   };

   $this->dliterator++;

   $uploaditerator++;
};

感谢所有的答案!这是我的工作解决方案,感谢Zuul:

if ($row['download'] != null){
if (($this->dliterator != null ) && ($check ==0)) {echo "<div class='clientsection' id='downloads'>Downloads</div><br/>";
$check++;};

Answer 1

试试这个:

$check=0;

if (($this->dliterator == 1) && ($check==0)) {
  echo "<div class='clientsection' id='downloads'>Downloads</div><br/>";
  $check++;
};

if如果您dliterator==1和if $check没有改变它将进入语句...在内部之后,它将改变$check因此阻止if语句再次运行!

希望能帮助到你!