正好需要3个参数(给出4个参数)

Question

我正在重构代码以添加面向对象而我只是测试代码.

pattern = r"((([01]?[0-9]?[0-9]|2[0-4][0-9]|25[0-5])[ (\[]?(\.|dot)[ )\]]?){3}([01]?[0-9]?[0-9]|2[0-4][0-9]|25[0-5]))"

class Lineobject(object):

        def __init__(self, pattern, line):
            self.ip = self.getip(self, pattern, line)

        def getip (self, pattern, line):
                for match in re.findall(pattern, line):
                    results = ''
                    ips = match[0]
                    usergeneratedblacklist.write(ips)
                    usergeneratedblacklist.write('\n')
                    return ips

在实例化下面的类时,我得到一个奇怪的错误.那个getip()需要3个参数(4个给定),我不知道如何解决.

for theline in f:

    if "Failed password" in theline:

        lineclass = Lineobject(pattern, theline)

    else:
        pass

Answer 1

您提供了self.getip()四个参数,因为Python会自动self为绑定方法添加第一个参数.表达方式:

self.getip(self, pattern, line)

结果是:

getip(self, self, pattern, line)

这是四个论点.

不要self再次传递:

self.ip = self.getip(pattern, line)

在实例上查找方法的行为(via self.getip)绑定方法来为您处理第一个参数.