我有一个变量有三个值,NA,Yes,MayBe.
当我在该变量上使用level和class函数时,我得到了这些值
> levels(Data1$Case)
"Yes" "May Be"
> class(Data1$Case)
"factor"
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我试图用No替换NA值,所以我使用此代码
Data1$Col1[is.na(Data1$Col1)]= "No"
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我收到一个错误,
In `[<-.factor`(`*tmp*`, is.na(Data1$Col1), value = c(NA, :
invalid factor level, NA generated
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我写了一个ifelse声明来取代NA,
Data1$Col1=ifelse(is.na(Data1$Col1_ == 'TRUE'), "No",Data1$Col1)
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这是有效的,但我正在寻找一些有效的方法来取代NA.
您可以使用addNA()
和levels<-
替换功能.
x <- factor(c(NA, "Yes", "Maybe"))
# [1] <NA> Yes Maybe
# Levels: Maybe Yes
## If present, add NA to the factor levels
addNA(x)
# [1] <NA> Yes Maybe
# Levels: Maybe Yes <NA>
y <- addNA(x)
## replace the NA level with 'No'
levels(y)[is.na(levels(y))] <- "No"
y
# [1] No Yes Maybe
# Levels: Maybe Yes No
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