ken*_*nan 6 grails grails-controller
我需要从我的网络应用程序中的任何控制器中读出所有可用的操作.这样做的原因是授权系统,我需要向用户提供允许的操作列表.
例如:用户xyz具有执行动作节目,列表,搜索的授权.用户admin具有执行操作编辑,删除等操作的权限.
我需要从控制器中读出所有动作.有没有人有想法?
这将创建一个带有控制器信息的地图列表('数据'变量).List中的每个元素都是一个带有键'controller'的Map,对应于控制器的URL名称(例如BookController - >'book'),对应于类名的controllerName('BookController')和对应的'actions' a该控制器的操作名称列表:
import org.springframework.beans.BeanWrapper
import org.springframework.beans.PropertyAccessorFactory
def data = []
for (controller in grailsApplication.controllerClasses) {
def controllerInfo = [:]
controllerInfo.controller = controller.logicalPropertyName
controllerInfo.controllerName = controller.fullName
List actions = []
BeanWrapper beanWrapper = PropertyAccessorFactory.forBeanPropertyAccess(controller.newInstance())
for (pd in beanWrapper.propertyDescriptors) {
String closureClassName = controller.getPropertyOrStaticPropertyOrFieldValue(pd.name, Closure)?.class?.name
if (closureClassName) actions << pd.name
}
controllerInfo.actions = actions.sort()
data << controllerInfo
}
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这是与Grails 2配合使用的示例,即它将捕获定义为方法或闭包的动作
import org.codehaus.groovy.grails.commons.DefaultGrailsControllerClass
import java.lang.reflect.Method
import grails.web.Action
// keys are logical controller names, values are list of action names
// that belong to that controller
def controllerActionNames = [:]
grailsApplication.controllerClasses.each { DefaultGrailsControllerClass controller ->
Class controllerClass = controller.clazz
// skip controllers in plugins
if (controllerClass.name.startsWith('com.mycompany')) {
String logicalControllerName = controller.logicalPropertyName
// get the actions defined as methods (Grails 2)
controllerClass.methods.each { Method method ->
if (method.getAnnotation(Action)) {
def actions = controllerActionNames[logicalControllerName] ?: []
actions << method.name
controllerActionNames[logicalControllerName] = actions
}
}
}
}
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