具有自己的功能的Open Bootstrap Model

Question

我有一个asp.net Web应用程序.当我点击我的按钮时,应该打开一个模态,这是我的按钮:

<input type="button" class="mybutton" data-toggle="modal"     data-target="#mymodal" value="Open Model" /> 

这工作正常,但我更喜欢这样:

<input type="button" class="mybutton" onclick="showModal()" value="Open Model" /> 

有:

function showModal() {
      $('#mymodal').toggle();
  }

但是当我这样做并单击按钮时,模态不会显示,就像整个页面冻结一样.但我没有收到任何错误警告.如果有人有想法,我会真的很高兴.

Answer 1

请参阅模态方法的 Bootstrap文档.

function showModal() {
  $('#myModal').modal('show');
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="//maxcdn.bootstrapcdn.com/bootstrap/3.3.4/js/bootstrap.min.js"></script>
<link href="//maxcdn.bootstrapcdn.com/bootstrap/3.3.4/css/bootstrap.min.css" rel="stylesheet"/>
<input type="button" class="mybutton btn btn-primary" onclick="showModal()" value="Open Model" /> 

<div class="modal fade" id="myModal" tabindex="-1" role="dialog" aria-labelledby="exampleModalLabel" aria-hidden="true">
  <div class="modal-dialog">
    <div class="modal-content">
      <div class="modal-header">
        <button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">&times;</span></button>
        <h4 class="modal-title" id="exampleModalLabel">Modal</h4>
      </div>
      <div class="modal-body">
        Modal content
      </div>
      <div class="modal-footer">
        <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
      </div>
    </div>
  </div>
</div>

您还有其他方法可以与模态进行交互,例如:

$('#myModal').modal('toggle'); // Show if closed, close if shown
$('#myModal').modal('show'); // Show modal
$('#myModal').modal('hide'); // Hide modal

Answer 2

你可以使用以下任何一种.

$('#myModal').modal('toggle');
$('#myModal').modal('show');
$('#myModal').modal('hide');

你可以在这里看到更多:模态