当我查询/mycollections?ql=Select * where name='dfsdfsdfsdfsdfsdf'我得到
{
"action" : "get",
"application" : "859e6180-de8a-11e4-9360-f1aabbc15f58",
"params" : {
"ql" : [ "Select * where name='dfsdfsdfsdfsdfsdf'" ]
},
"path" : "/mycollections",
"uri" : "http://localhost:8080/myorg/myapp/mycollections",
"entities" : [ {
"uuid" : "2ff8961a-dea8-11e4-996b-63ce373ace35",
"type" : "mycollection",
"name" : "dfsdfsdfsdfsdfsdf",
"created" : 1428577466865,
"modified" : 1428577466865,
"metadata" : {
"path" : "/mycollections/2ff8961a-dea8-11e4-996b-63ce373ace35",
"connections" : {
"relations" : "/mycollections/2ff8961a-dea8-11e4-996b-63ce373ace35/relations"
}
}
} ],
"timestamp" : 1428589309204,
"duration" : 53,
"organization" : "myorg",
"applicationName" : "myapp",
"count" : 1
}
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现在如果我查询/mycollections/2ff8961a-dea8-11e4-996b-63ce373ace35/relations我得到第二个实体
{
"action" : "get",
"application" : "859e6180-de8a-11e4-9360-f1aabbc15f58",
"params" : { },
"path" : "/mycollections/2ff8961a-dea8-11e4-996b-63ce373ace35/relations",
"uri" : "http://localhost:8080/myorg/myapp/mycollections/2ff8961a-dea8-11e4-996b-63ce373ace35/relations",
"entities" : [ {
"uuid" : "56a1185a-dec1-11e4-9ac0-e9343f86b604",
"type" : "secondcollection",
"name" : "coucou",
"created" : 1428588269141,
"modified" : 1428588269141,
"metadata" : {
"connecting" : {
"relations" : "/mycollections/2ff8961a-dea8-11e4-996b-63ce373ace35/relations/56a1185a-dec1-11e4-9ac0-e9343f86b604/connecting/relations"
},
"path" : "/mycollections/2ff8961a-dea8-11e4-996b-63ce373ace35/relations/56a1185a-dec1-11e4-9ac0-e9343f86b604"
}
} ],
"timestamp" : 1428589668542,
"duration" : 51,
"organization" : "myorg",
"applicationName" : "myapp"
}
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我想要的是,不是向我提供相关实体的路径,而是将Usergrid直接嵌套在第一个JSON答案中,这样我只需要生成一个http请求而不是两个.
不确定您使用的是什么数据库。如果您使用像 mongo 这样的文档数据库,那么您可以编写一个 Node.js 脚本来执行此操作。Apigee 有 volvo.js 检查是否可以执行脚本。
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