从SearchView开始新活动

Question

我有2个活动:第一个有一个带有搜索视图的操作栏,第二个应该显示搜索查询的结果.

androidmanifest:

    <activity
        android:name=".SearchActivity"

        ...
        android:launchMode="singleTop">           

        <meta-data
            android:name="android.app.searchable"
            android:resource="@xml/searchable" />
        ...

    </activity>

   <activity
        android:name=".ResultsActivity"
        ...

         <intent-filter>
            <action android:name="android.intent.action.SEARCH" />
        </intent-filter>

    </activity>

searchable.xml

<searchable
xmlns:android="http://schemas.android.com/apk/res/android"
android:label="@string/app_name"
android:hint="@string/enter_a_word" />

SearchActivity

....
@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.menu_noun_list, menu);

    // Associate searchable configuration with the SearchView
    SearchManager searchManager =  (SearchManager) getSystemService(Context.SEARCH_SERVICE);
    SearchView searchView =  (SearchView) menu.findItem(R.id.search).getActionView();
    searchView.setSearchableInfo( searchManager.getSearchableInfo(getComponentName()));

    return true;
}
....

ResultsActivity:

@Override
protected void onCreate(Bundle savedInstanceState) {
    ...
if (Intent.ACTION_SEARCH.equals(intent.getAction())) {
        String query = intent.getStringExtra(SearchManager.QUERY);

    }
...
}

问题是在查询输入搜索视图后,没有任何反应.没有错误,没有.在查询中输入查询后,如何打开结果活动？

Answer 1

这个答案有点晚,但我觉得它对未来的观众有用.这种困境似乎来自Android SearchView教程的含糊不清.它们涵盖的场景假定您将在SearchView所在的同一个Activity中显示结果.在这种情况下,AndroidManifest.xml文件中的Activity标记看起来像这样:

<activity
    android:name=".MainActivity"
    android:label="@string/main_activity_label"
    android:launchMode="singleTop">
        <intent-filter>
            <action android:name="android.intent.action.SEARCH"/>
        </intent-filter>
        <meta-data android:name="android.app.searchable"
            android:resource="@xml/searchable" />
</activity>

然后,要在同一个Activity中处理结果,您将覆盖该onNewIntent方法:

@Override
public void onNewIntent(Intent intent){
    setIntent(intent);
    if(Intent.ACTION_SEARCH.equals(intent.getAction())) {
        String query = intent.getStringExtra(SearchManager.QUERY);
        //now you can display the results
    }  
}

但是,在我们想要在另一个Activity中显示结果的情况下,我们必须将Intent Filter和meta标记放入结果Activity中,并为SearchView Activity引入一个新的元标记.所以,我们的活动在AndroidManifest.xml文件中看起来像这样:

<activity
        android:name=".MainActivity"
        android:label="@string/main_activity_label"
        android:launchMode="singleTop">
        <!-- meta tag points to the activity which displays the results -->
        <meta-data
            android:name="android.app.default_searchable"
            android:value=".SearchResultsActivity" />
</activity>
<activity
        android:name=".SearchResultsActivity"
        android:label="@string/results_activity_label"
        android:parentActivityName="com.example.MainActivity">
        <!-- Parent activity meta-data to support 4.0 and lower -->
        <meta-data
            android:name="android.support.PARENT_ACTIVITY"
            android:value="com.example.MainActivity" />
        <!-- meta tag and intent filter go into results activity -->
        <meta-data android:name="android.app.searchable"
            android:resource="@xml/searchable" />
        <intent-filter>
            <action android:name="android.intent.action.SEARCH" />
        </intent-filter>
</activity>

然后,在我们的MainActivity的onCreateOptionsMenu方法中,激活SearchView(假设您将SearchView添加到ActionBar).getComponentName()我们使用MainActivity的上下文和SearchResultsActivity类来实例化一个新的ComponentName对象,而不是在SearchManager的getSearchableInfo()方法调用中使用:

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.menu_home, menu);
    SearchView search = (SearchView) MenuItemCompat.getActionView(menu.findItem(R.id.action_search);
    // Associate searchable configuration with the SearchView
    SearchManager searchManager = (SearchManager) getSystemService(Context.SEARCH_SERVICE);
    search.setSearchableInfo(searchManager.getSearchableInfo(new ComponentName(this, SearchResultsActivity.class)));
    search.setQueryHint(getResources().getString(R.string.search_hint));
    return true;
}

最后,在我们的SearchResultsActivity类中,在onCreate方法中,我们可以处理搜索结果:

@Override
public void onCreate(Bundle savedInstanceState){
    super.onCreate(savedInstanceState);
    if (Intent.ACTION_SEARCH.equals(intent.getAction())) {
        String query = intent.getStringExtra(SearchManager.QUERY);
        //use the query to search your data somehow
    }
}

不要忘记创建searchable.xml资源文件并将SearchView添加到您的布局中.

searchable.xml(res/xml/searchable.xml;如果需要,在res下创建xml文件夹):

<?xml version="1.0" encoding="utf-8"?>
<searchable xmlns:android="http://schemas.android.com/apk/res/android"
    android:label="@string/app_name"
    android:hint="@string/search_hint"
    android:voiceSearchMode="showVoiceSearchButton|launchRecognizer"/>

布局(将SearchView添加到ActionBar作为菜单项的示例):

<menu xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:app="http://schemas.android.com/apk/res-auto"
    xmlns:tools="http://schemas.android.com/tools"
    tools:context="com.example.MainActivity">
    <group android:checkableBehavior="single">
        <item android:id="@+id/action_search" android:title="Search"
            android:orderInCategory="1" app:showAsAction="collapseActionView|ifRoom"
            app:actionViewClass="android.support.v7.widget.SearchView"/>
    </group>
</menu>

资源:

• 显示相同活动的结果
• 显示不同活动的结果
• 组件名称