use*_*591 1 database mongodb nosql mongodb-query aggregation-framework
我有一个包含数组的文档。就像这样:
"_id" : ObjectId("55101f81e4b07caf8554b9b1"),
"myId" : "1222222",
"isDelayed" : false,
"status" : "BALLS",
"yellow" : false,
"white" : true,
"people" : [
{
"peopleId" : 222222,
"bc" : 0,
"status" : "live",
"fc" : 1,
"tc": 4,
"rc": "yellow"
},
{
"peopleId" : 33312,
"bc" : 0,
"status" : "live",
"fc" : 1,
"tc": 4,
"rc": "yellow"
},
...
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我有一个如下所示的 mongo 查询,在 collection 中mycoll,如果myId=1.222在 people 数组中,如果people.peopleId=1123它返回第一个匹配项:
db.getCollection('mycoll').find(
{myId:'1.222',
people: { $elemMatch: { peopleId: 1123 }
}
},{"people.$": 1 }).pretty();
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结果包括数组中人员条目中的所有字段:
"people" : [
{
"peopleId" : 1122,
"bc" : 0,
"status" : "live",
"fc" : 1,
"tc": 4,
"rc": "yellow"
},
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如何过滤答复,使其仅从内部数组中的匹配"status"条目返回所需的字段?我可以为外部文档生成过滤器,但不能为数组元素中的字段生成过滤器。
您可以使用聚合来完成此操作。你需要做的是:
myId.people数组,以便内部每个子文档都有一个文档people。peopleId.db.mycoll.aggregate([
{ "$match": { "myId": "1.222"} },
{ "$unwind": "$people" },
{ "$match": { "people.peopleId": 1123 }},
{ "$project": { "peopleId": "$people.peopleId",
"status": "$people.status" }
}
]).pretty();
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