Man*_*esh 5 android android-emulator
我想在android中以编程方式提交表单.我不希望任何用户与Web浏览器进行交互.用户将在EditField中提供输入,然后输入将通过HTTP post方法通过HTTPwebmethod提交.但我没有取得任何成功.请指教.我在java中使用过HTMLUnit但它在android中不起作用.
final WebClient webClient = new WebClient();
final HtmlPage page1 = webClient.getPage("http://www.mail.example.com");
final HtmlForm form = page1.getHtmlElementById("loginform");
final HtmlSubmitInput button = form.getInputByName("btrn");
final HtmlTextInput textField1 = form.getElementById("user");
final HtmlPasswordInput textField2 = form.getElementById("password");textField1.setValueAttribute("user.name");
textField2.setValueAttribute("pass.word"); final HtmlPage page2 = button.click();
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all*_*aws 11
哎呀.抱歉.看起来你正试图通过浏览器发布POST.
这是我在Android中用来完成HTTP POST的代码片段,无需通过网络浏览器:
HttpClient httpClient = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(httpClient.getParams(), TIMEOUT_MS);
HttpConnectionParams.setSoTimeout(httpClient.getParams(), TIMEOUT_MS);
HttpPost httpPost = new HttpPost(url);
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("name1", "value1"));
nameValuePairs.add(new BasicNameValuePair("name2", "value2"));
nameValuePairs.add(new BasicNameValuePair("name3", "value3"));
// etc...
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpClient.execute(httpPost);
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我认为这应该适用于你想要做的事情.我将TIMEOUT_MS设置为10000(所以,10秒)
然后你可以使用以下内容读出服务器的响应:
BufferedReader br = new BufferedReader(new InputStreamReader(response.getEntity().getContent()), 8096);
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