'(String) - > AnyObject?' 不能转换为'ResultCell'

Sec*_*Son 1 uitableview ios swift xcode6

我正在尝试投射我自己的自定义单元格,但似乎没有工作,我是IOS的新手和快速开发...从教程我看它工作正常但是当我尝试时,它给了我一个错误.
这是代码.

class UsersViewController: UIViewController, UITableViewDelegate, UITableViewDataSource{

@IBOutlet weak var resultTable: UITableView!

override func viewDidLoad() {
    super.viewDidLoad()

    let height = view.frame.height
    let width = view.frame.width

}


func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    return 1
}

func tableView(tableView: UITableView, heightForRowAtIndexPath indexPath: NSIndexPath) -> CGFloat {
    return 120
}

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {

    var cell : ResultCell = UITableView.dequeueReusableCellWithIdentifier("userCell") as ResultCell

    return cell
}

func tableView(tableView: UITableView, moveRowAtIndexPath sourceIndexPath: NSIndexPath, toIndexPath destinationIndexPath: NSIndexPath) {

}
// Deactivate the return button 
override func viewWillAppear(animated: Bool) {
    self.navigationItem.hidesBackButton = true
}


 }
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这是我创建的单元格

  class ResultCell: UITableViewCell {

@IBOutlet weak var ContactprofilePic: UIImageView!
@IBOutlet weak var contactUserName: UILabel!
@IBOutlet weak var contactStatus: UILabel!

override func awakeFromNib() {
    super.awakeFromNib()
    // Initialization code
    let aWidth = UIScreen.mainScreen().bounds.width
    contentView.frame = CGRectMake(0, 0, aWidth, 120)

    ContactprofilePic.center = CGPointMake(60, 60)
    ContactprofilePic.layer.cornerRadius = ContactprofilePic.frame.size.width/2
    ContactprofilePic.clipsToBounds = true

    contactUserName.center = CGPointMake(230, 55)
}

override func setSelected(selected: Bool, animated: Bool) {
    super.setSelected(selected, animated: animated)

    // Configure the view for the selected state
}

  }
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但后来我收到了这个错误

(String) - > AnyObject?' 不能转换为'ResultCell'

Mar*_*n R 5

UITableView.dequeueReusableCellWithIdentifier(...)
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应该

tableView.dequeueReusableCellWithIdentifier(...)
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dequeueReusableCellWithIdentifier()是一个实例方法,必须在tableView作为第一个参数传递给该cellForRowAtIndexPath方法的实例上调用.


实际上是表达方式

UITableView.dequeueReusableCellWithIdentifier
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是有效的,如http://oleb.net/blog/2014/07/swift-instance-methods-curried-functions/中所述.该表达式的值是该类型的"curried函数"

(UITableView) -> (String) -> AnyObject?
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这很可能不是您打算做的,但解释了错误消息

(String) -> AnyObject?' is not convertible to 'ResultCell'