PopupMenu单击导致RecyclerView滚动

Question

我有一个内部的溢出按钮CardView在Recyclerview.每当我点击按钮时,我会显示一个弹出菜单,但也会RecyclerView向下滚动一个项目.谁能帮助我阻止这种不必要的滚动？

基本上我试图复制与Playstore中相同的溢出按钮行为.

布局:

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_margin="5dp">

<android.support.v7.widget.CardView
    android:id="@+id/cv_tracks"
    android:layout_width="match_parent"
    android:layout_height="65dp"
    >

    <RelativeLayout
        android:layout_width="match_parent"
        android:layout_height="60dp">

        <ImageView
            android:id="@+id/ivTracks"
            android:layout_width="60dp"
            android:layout_height="60dp"
            android:background="@drawable/unknown"
           />
        <Button
            android:id="@+id/imgbtn_overflow"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:background="@android:color/transparent"
            android:drawableTop="@drawable/ic_overflow"
            android:paddingLeft="25dp"
            android:paddingRight="20dp"
            android:layout_alignParentTop="true"
            android:layout_centerHorizontal="true" /> 
 </RelativeLayout>
 </android.support.v7.widget.CardView>
 </RelativeLayout>

适配器:

@Override
public void onBindViewHolder(final TracksViewHolder tracksViewHolder, int i) {

    tracksViewHolder.imgBtnOverflow.setTag(i);
    tracksViewHolder.imgBtnOverflow.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            //Creating the instance of PopupMenu
            final int position = (Integer) v.getTag();

            PopupMenu popup = new PopupMenu(mContext,tracksViewHolder.imgBtnOverflow);

            //Inflating the Popup using xml file
            popup.getMenuInflater()
                    .inflate(R.menu.popup_menu_overflow, popup.getMenu());


            //registering popup with OnMenuItemClickListener
            popup.setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() {

                public boolean onMenuItemClick(MenuItem item) {

                 if(mPopUpClick!=null)
                     mPopUpClick.actionOnPopUpItemClick(position,item,songs.get(position));
                    return true;
                }
            });

            popup.show(); //showing popup menu
        }
    });

}

更新: 遇到问题.当弹出菜单显示时,它会向下滑动列表以显示整个下拉列表.如何根据可用空间调整弹出窗口上/下显示？

Answer 1

尝试使用android.widget.PopupMenu而不是android.support.v7.widget.PopupMenu和Voila,它的工作原理.这是支持库中的一个错误.伟大的开发人员可以在这里确认一样吗？

Answer 2

您可以让您的AnchorView覆盖requestRectangleOnScreen()并返回false.这将阻止任何父级ScrollView滚动.

所以,在你的情况下,imgBtnOverflow将是一个习惯ImageButton,如下:

/**
 * A custom {@link ImageButton} which prevents parent ScrollView scrolling when used as the
 * anchor for a {@link android.support.v7.widget.PopupMenu}
 */
public class NonScrollImageButton extends ImageButton {

    public NonScrollImageButton(Context context, AttributeSet attrs) {
        super(context, attrs);
    }

    @Override
    public boolean requestRectangleOnScreen(Rect rectangle, boolean immediate) {
        return false;
    }
}

jankovd的道具(https://gist.github.com/jankovd/19ef35efd1f00e9213fa)

此处针对支持PopupMenu提出了一个问题:https://code.google.com/p/android/issues/detail？ id = 135439