Python - 检查字符串是否包含列表中的任何元素

Question

我需要检查字符串是否包含列表的任何元素.我目前正在使用这种方法:

engWords = ["the", "a", "and", "of", "be", "that", "have", "it", "for", "not"]
engSentence = "the dogs fur is black and white"

print("the english sentence is: " + engSentence)

engWords2 = []
isEnglish = 0

for w in engWords:
    if w in engSentence:
        isEnglish = 1
        engWords2.append(w)

if isEnglish == 1:
    print("The sentence is english and contains the words: ")
    print(engWords2)

这个问题是它给出了输出:

the english sentence is: the dogs fur is black and white
The sentence is english and contains the words: 
['the', 'a', 'and', 'it']
>>> 

你可以看到'a'和'it'不应该存在.我如何搜索,以便它只列出单个单词,而不是单词的一部分？我对使用普通python代码或正则表达式的任何想法持开放态度(虽然我对python和regex都很新,所以请不要太复杂)谢谢.

Answer 1

它找到了这两个词,因为它们分别是"黑色"和"白色"的子串.将"in"应用于字符串时,它只查找字符的子字符串.

尝试:

engSentenceWords = engSentence.split()

然后,

if w in engSentenceWords:

将原始句子分成单个单词列表,然后检查整个单词值.