可能的重复:
枚举C++
C++中的枚举:迭代枚举
我有一个二十一点游戏的卡片类,有以下枚举:
enum Rank { Ace, Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten, Jack, Queen, King };
enum Suit { Clubs, Diamonds, Hearts, Spades };
Run Code Online (Sandbox Code Playgroud)
当我创建甲板时,我想编写如下代码:
// foreach Suit in Card::Suit
// foreach Rank in Card::Rank
// add new card(rank, suit) to deck
Run Code Online (Sandbox Code Playgroud)
我相信c ++中没有foreach.但是,我如何遍历枚举?
谢谢,斯宾塞
Mtn*_*ark 20
enum
为了方便起见,通常会添加元素:
enum Rank {
Ace, Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten, Jack, Queen, King,
RankFirst = Ace, RankLast = King
};
enum Suit {
Clubs, Diamonds, Hearts, Spades,
SuitFirst = Clubs, SuitLast = Spades
};
Run Code Online (Sandbox Code Playgroud)
然后你可以编写你的循环:
for (int r = RankFirst; r <= RankLast; ++r) {
for (int s = SuitFirst; s <= SuitLast; ++s) {
deck.add(Card((Rank)r, (Suit)s));
}
}
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
10197 次 |
最近记录: |