如何从odbc获取主机名和端口

Question

嗨,我已经配置了系统DSN,它运行良好.所以我忘记了主机名地址和端口号,怎么能通过它找到它？当我选择数据源并单击configure时,它只告诉我用户ID和dbalias.我也查看了注册表,只找到这样的东西

"Windows注册表编辑器版本5.00

[HKEY_LOCAL_MACHINE\SOFTWARE\ODBC\ODBC.INI\BUS]"Driver"="C:\ PROGRA~1\IBM\SQLLIB\BIN\DB2CLIO.DLL"

"""

Answer 1

DB2数据库连接由计算机上的DB2客户端软件配置.在客户端软件中定义连接后,它们将显示在"ODBC数据源"面板中.您无法通过控制面板进行配置.

要查看它们,请打开DB2命令窗口,然后发出命令db2 list db directory.这将列出您的系统知道的所有数据库:

C:\Program Files\IBM\SQLLIB\BIN>db2 list db directory

 System Database Directory

 Number of entries in the directory = 2

Database 1 entry:

 Database alias                       = SAMPLE
 Database name                        = SAMPLE
 Node name                            = DB2AED1
 Database release level               = 10.00
 Comment                              =
 Directory entry type                 = Remote
 Catalog database partition number    = -1
 Alternate server hostname            =
 Alternate server port number         =

Database 2 entry:

 Database alias                       = IBMDSMR
 Database name                        = IBMDSMR
 Local database directory             = C:
 Database release level               = 10.00
 Comment                              =
 Directory entry type                 = Indirect
 Catalog database partition number    = 0
 Alternate server hostname            =
 Alternate server port number         =

在上面的示例中,"目录条目类型"表示数据库是本地的("间接"),即您的计算机上是否运行了DB2服务器),或者数据库是远程的("远程"),如SAMPLE数据库以上.

要查看连接详细信息SAMPLE,请记下节点名称(DB2AED1在上面的示例中)并发出db2 list node directory命令:

C:\Program Files\IBM\SQLLIB\BIN>db2 list node directory

 Node Directory

 Number of entries in the directory = 1

Node 1 entry:

 Node name                      = DB2AED1
 Comment                        =
 Directory entry type           = LOCAL
 Protocol                       = TCPIP
 Hostname                       = mydb2.stackoverflow.com
 Service name                   = 50000

您可以看到它DB2AED1位于主机mydb2.stackoverflow.com和端口上50000.如果由于某种原因,"服务名称"字段有一个名称,那么您需要在服务文件中查找(%windir%\system32\drivers\etc\services在Windows或/etc/servicesLinux上)