JQ: setdiff of two arrays

Question

If I have an object with two arrays containing unique values in it

{"all":["A","B","C","ABC"],"some":["B","C"]}

How can I find .all - .some?

在这种情况下，我正在寻找 ["A","ABC"]

Answer 1

@Jeff Mercado 让我大吃一惊！我不知道允许数组减法...

echo -n '{"all":["A","B","C","ABC"],"some":["B","C"]}' | jq '.all-.some'

产量

[
  "A",
  "ABC"
]