str*_*iwi 0 python mysql django django-taggit
我正在尝试选择3个最近发布的项目,其中任何标签与当前项目类似(以及其他一些过滤器)无法找到有效的方法,数据库中有很多"项目".
from taggit_autosuggest.managers import TaggableManager
class Item(models.Model):
publish_date = DateField()
tags = TaggableManager()
sites = ManyToManyField(Site)
def my_view():
...
current_item = #get current item
related_items = Item.active_objects.filter(
sites=current_site,
id__in=[x.id for x in current_item.tags.similar_objects()]
).order_by('-publish_date')[:3]
...
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但是这会从similar_objects()方法引起相当大的性能问题.current_item具有的标签越多,指数越差
# Query_time: 20.613503 Lock_time: 0.000182 Rows_sent: 83 Rows_examined: 7566504
SELECT `taggit_taggeditem`.`content_type_id`, `taggit_taggeditem`.`object_id`, COUNT(`taggit_taggeditem`.`id`) AS `n` FROM `taggit_taggeditem` WHERE (NOT (`taggit_taggeditem`.`object_id` = 205636 AND `taggit_taggeditem`.`content_type_id`
= 11 ) AND (`taggit_taggeditem`.`tag_id`) IN (SELECT DISTINCT `taggit_tag`.`id` FROM `taggit_tag` INNER JOIN `taggit_taggeditem` ON ( `taggit_tag`.`id` = `taggit_taggeditem`.`tag_id` ) WHERE (`taggit_taggeditem`.`object_id` = 205636 AND
`taggit_taggeditem`.`content_type_id` = 11 ))) GROUP BY `taggit_taggeditem`.`content_type_id`, `taggit_taggeditem`.`object_id` ORDER BY `n` DESC;
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我也试过不使用类似的对象方法
related_items = Item.active_objects.filter(
sites=current_site,
tags__in=current_item.tags.all()).exclude(slug=slug).order_by('-publish_date').distinct()[:3]
context['tagged'] = tags.order_by('-publish_date').distinct()[:3]
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这一直是更糟糕的(一些查询高达120s,yuck)
这样做的"好"方法是什么?!
我的假设是获取标签,并使用tag-> item关系比搜索所有项目更有效.因此,我们构建了所有TaggedItem的查询集,获取所有对象的ID,然后执行我们的过滤器.
from taggit.models import TaggedItem
related_items = TaggedItem.objects.none()
for tag in current_item.tags.all():
#build queryset of all TaggedItems
related_items |= tag.taggit_taggeditem_items.all()
#TaggedItem doesn't have a direct link to the object, have to grab ids
ids = related_items.values_list('object_id', flat=True)
return Item.objects.filter(id__in=ids, sites=current_site).exclude(id=item.id).order_by('-publish_date')[:3]
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