fre*_*low 14 java string scala hashcode switch-statement
我很想知道Java和Scala如何在字符串上实现切换:
class Java
{
public static int java(String s)
{
switch (s)
{
case "foo": return 1;
case "bar": return 2;
case "baz": return 3;
default: return 42;
}
}
}
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object Scala {
def scala(s: String): Int = {
s match {
case "foo" => 1
case "bar" => 2
case "baz" => 3
case _ => 42
}
}
}
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看起来Java会切换哈希码,然后进行单个字符串比较:
0: aload_0
1: dup
2: astore_1
3: invokevirtual #16 // Method java/lang/String.hashCode:()I
6: lookupswitch { // 3
97299: 40
97307: 52
101574: 64
default: 82
}
40: aload_1
41: ldc #22 // String bar
43: invokevirtual #24 // Method java/lang/String.equals:(Ljava/lang/Object;)Z
46: ifne 78
49: goto 82
52: aload_1
53: ldc #28 // String baz
55: invokevirtual #24 // Method java/lang/String.equals:(Ljava/lang/Object;)Z
58: ifne 80
61: goto 82
64: aload_1
65: ldc #30 // String foo
67: invokevirtual #24 // Method java/lang/String.equals:(Ljava/lang/Object;)Z
70: ifne 76
73: goto 82
76: iconst_1
77: ireturn
78: iconst_2
79: ireturn
80: iconst_3
81: ireturn
82: bipush 42
84: ireturn
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相比之下,Scala似乎与所有案例进行比较:
0: aload_1
1: astore_2
2: ldc #16 // String foo
4: aload_2
5: invokevirtual #20 // Method java/lang/Object.equals:(Ljava/lang/Object;)Z
8: ifeq 16
11: iconst_1
12: istore_3
13: goto 47
16: ldc #22 // String bar
18: aload_2
19: invokevirtual #20 // Method java/lang/Object.equals:(Ljava/lang/Object;)Z
22: ifeq 30
25: iconst_2
26: istore_3
27: goto 47
30: ldc #24 // String baz
32: aload_2
33: invokevirtual #20 // Method java/lang/Object.equals:(Ljava/lang/Object;)Z
36: ifeq 44
39: iconst_3
40: istore_3
41: goto 47
44: bipush 42
46: istore_3
47: iload_3
48: ireturn
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是否有可能说服Scala使用哈希码技巧?我宁愿选择O(1)解决方案来解决O(n)问题.在我的真实代码中,我需要与33个可能的关键字进行比较.
肯定看来这个案例是Scala编译器缺乏优化.当然,该match构造比Java中的switch/case强大得多(并且非常强大),并且优化它要困难得多,但它可以检测这些特殊情况,其中将应用简单的哈希比较.
此外,我不认为这个案例会在惯用的Scala中多次出现,因为除了具有不同的值之外,你总是与具有某种意义的案例类相匹配.
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