MAC*_*MAC 2 ruby json ruby-on-rails clause sql-like
我想在搜索关键字时获得数据的json格式,所以我使用LIKE子句和这样的查询
"select * from employees where fname like ? or mname like ? or lname like ? or username like ? or id like ?", str, str, str, str, str
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但我想用rails编写代码.我的控制器中有这个代码
def showemployees
str = params[:str]
render json: @employee = Employee.where(Employee.employees[:fname].matches("%#{str}%")) or
(Employee.employees[:mname].matches("%#{str}%")) or
(Employee.employees[:lname].matches("%#{str}%")) or
(Employee.employees[:id].matches("%#{str}%"))
end
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这个代码在我的config/routes.rb中
get 'employees/showemployees'
root :to => 'employees#new'
resources :employees
post 'employees/update_info'
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当我输入这个,http:// localhost:3000/employees/showemployees?str = samplename,该记录的json格式应该出现但我收到此错误消息
undefined method `employees' for #<Class:0x8e38900>
app/controllers/employees_controller.rb:6:in `showemployees'
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第6行有此代码
render json: @employee = Employee.where(Employee.employees[:fname].matches("%#{str}%")) or
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您可以链接查询的位置,但AND每个查询结果都在哪里
Employee.where('fname LIKE ?', "%#{str}%").where('lname LIKE ?', "%#{str}%").where('mname LIKE ?', "%#{str}%").where('username LIKE ?', "%#{str}%").where('id LIKE ?', "%#{str}%")
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或使用OR条款
Employee.where('fname LIKE ? OR lname LIKE ? OR mname', "%#{str}%", "%#{str}%", "%#{str}%")
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