如何在rails中使用like子句查询?

MAC*_*MAC 2 ruby json ruby-on-rails clause sql-like

我想在搜索关键字时获得数据的json格式,所以我使用LIKE子句和这样的查询

"select * from employees where fname like ? or mname like ? or lname like ? or username like ? or id like ?", str, str, str, str, str
Run Code Online (Sandbox Code Playgroud)

但我想用rails编写代码.我的控制器中有这个代码

def showemployees
  str = params[:str]
  render json: @employee = Employee.where(Employee.employees[:fname].matches("%#{str}%")) or
    (Employee.employees[:mname].matches("%#{str}%")) or
    (Employee.employees[:lname].matches("%#{str}%")) or
    (Employee.employees[:id].matches("%#{str}%"))
end
Run Code Online (Sandbox Code Playgroud)

这个代码在我的config/routes.rb中

get 'employees/showemployees'
root :to => 'employees#new'
resources :employees
post 'employees/update_info'
Run Code Online (Sandbox Code Playgroud)

当我输入这个,http:// localhost:3000/employees/showemployees?str = samplename,该记录的json格式应该出现但我收到此错误消息

undefined method `employees' for #<Class:0x8e38900>
app/controllers/employees_controller.rb:6:in `showemployees'
Run Code Online (Sandbox Code Playgroud)

第6行有此代码

render json: @employee = Employee.where(Employee.employees[:fname].matches("%#{str}%")) or
Run Code Online (Sandbox Code Playgroud)

Son*_*ute 7

您可以链接查询的位置,但AND每个查询结果都在哪里

Employee.where('fname LIKE ?', "%#{str}%").where('lname LIKE ?', "%#{str}%").where('mname LIKE ?', "%#{str}%").where('username LIKE ?', "%#{str}%").where('id LIKE ?', "%#{str}%")
Run Code Online (Sandbox Code Playgroud)

或使用OR条款

Employee.where('fname LIKE ? OR lname LIKE ? OR mname', "%#{str}%", "%#{str}%", "%#{str}%")
Run Code Online (Sandbox Code Playgroud)

  • 您可以使用[命名占位符](http://guides.rubyonrails.org/v4.2.1/active_record_querying.html#placeholder-conditions)减少重复:`Employee.where('fname LIKE:q OR lname LIKE:q或者mname LIKE:q',q:"%#{str}%")`. (3认同)