从ng-options选项中过滤ng-options

web*_*ean 9 angularjs angularjs-ng-repeat ng-options angularjs-ng-options

我希望能解决三个问题......

在我的应用页面中,我有一个选择状态,另一个选择县.对于我所拥有的州:

<select ng-model="filter.stateID" ng-options="item.stateID as item.state for item in st_option">
</select>
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数据:

[
  { state="California", stateID="5"},
  { state="Arizona", stateID="3"},
  { state="Oregon", stateID="38"},
  { state="Texas", stateID="44"},
  { state="Utah", stateID="45"},
  { state="Nevada", stateID="29"}
]
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对于我的县选择我有:

<select ng-model="filter.countyID" ng-options="item.countyID as item.county for item in co_option">
 </select>
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数据:

[
  { county="Orange", countyID="191", co_state_id="5"},
  { county="Multiple Counties", countyID="3178", co_state_id="3"},
  { county="Sonoma", countyID="218", co_state_id="38"},
  { county="Los Angeles", countyID="190", co_state_id="44"}
]
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这是我的ng-repeat:

<div ng-repeat="project in projects | filter:filter">
    <div>
        State: {{project.state}}<br> 
        County: {{project.county}}<br>
        <span ng-hide="{{project.stateID}}"></span>
        <span ng-hide="{{project.countyID}}"></span>
    </div>
</div>
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所以,正如你可以看到我正在使用stateID状态选择和县选择我co_state_id在县数据集中设置相应的状态ID .

我想做一些事情:

  1. 隐藏县选择,直到选择状态.
  2. 选择状态后,按选定的stateID/ 筛选县选择选项co_state_id
  3. 筛选ng-repeat由第一stateID,然后由countyID.

我还没有看到一个方法来设置filter.stateIDtrue由数字,而不是字符串或过滤器.当我使用stateID进行过滤时,我会得到混合结果,因为有些stateID人可以使用"1".

DTi*_*ing 28

通常你只想在每个帖子上提出一个问题,但我会给这三个问题一个机会.

第1部分:添加ng-showfor filter.stateID.由于您无法取消选择状态,因此如果角度为^ 1.3,则可以使用一次性绑定.

<select ng-show="::filter.stateID" ng-model="filter.countyID" ng-options="item.countyID as item.county for item in co_option">
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第2部分:添加过滤器{co_state_id : filter.stateID}

<select ng-show="::filter.stateID != null" ng-model="filter.countyID" ng-options="item.countyID as item.county for item in co_option | filter:{ co_state_id : filter.stateID }">
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第3部分:

您正在使用模式对象作为过滤器,如果id的值为1则无关紧要:

对象:模式对象可用于过滤数组包含的对象的特定属性.例如{name:"M",phone:"1"}谓词将返回一个项目数组,其属性名称包含"M",属性手机包含"1".可以使用特殊属性名称$(如{$:"text"})来接受对象的任何属性或其嵌套对象属性的匹配.这相当于如上所述与字符串匹配的简单子字符串.可以通过在字符串前加上!来取消谓词.例如{name:"!M"}谓词将返回一个属性名称不包含"M"的项目数组.

工作片段

var app = angular.module('app', []);

app.controller('myController', function($scope) {
  $scope.projects = [{
    name: 'Project1',
    state: 'CA',
    stateID: '5',
    county: 'Orange',
    countyID: '191'
  }, {
    name: 'Project2',
    state: 'CA',
    stateID: '5',
    county: 'LosAngeles',
    countyID: '190'
  }, {
    name: 'Project3',
    state: 'CA',
    stateID: '5',
    county: 'Orange',
    countyID: '191'
  }, {
    name: 'Project4',
    state: 'MadeUp',
    stateID: '1',
    county: 'MadeUp',
    countyID: '190'
  }];

  $scope.st_option = [{
    state: "California",
    stateID: "5"
  }, {
    state: "Arizona",
    stateID: "3"
  }, {
    state: "Oregon",
    stateID: "38"
  }, {
    state: "Texas",
    stateID: "44"
  }, {
    state: "Utah",
    stateID: "45"
  }, {
    state: "Nevada",
    stateID: "29"
  }];

  $scope.co_option = [{
    county: "Orange",
    countyID: "191",
    co_state_id: "5"
  }, {
    county: "Multiple Counties",
    countyID: "3178",
    co_state_id: "3"
  }, {
    county: "Sonoma",
    countyID: "218",
    co_state_id: "38"
  }, {
    county: "Los Angeles",
    countyID: "190",
    co_state_id: "44"
  }];

  $scope.filter = {};
});
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<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.3.15/angular.min.js"></script>
<div ng-app='app' ng-controller='myController'>
  <select ng-model="filter.stateID" 
          ng-options="item.stateID as item.state for item in st_option"></select>
  <select ng-show="::filter.stateID" 
          ng-model="filter.countyID" 
          ng-options="item.countyID as item.county for item in co_option | filter:{ co_state_id : filter.stateID }">
  </select>

  <div ng-repeat="project in projects | filter:filter">
    <div>
      <br>Name: {{ project.name }}
      <br>State: {{project.state}}
      <br>County: {{project.county}}
      <br>
      <span ng-hide="{{project.stateID}} "></span>
      <span ng-hide="{{project.countyID}} "></span>
    </div>
  </div>
</div>
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