use*_*629 7 python django celery
我在Ubuntu EC2节点上有一个Django项目,我一直用它来设置异步使用Celery
.
我已经能够在命令行中完成一项基本任务,使用:
(env1)ubuntu@ip-172-31-22-65:~/projects/tp$ celery --app=myproject.celery:app worker --loglevel=INFO
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我刚才意识到,我的队列中有很多任务,没有执行:
[2015-03-28 16:49:05,916: WARNING/MainProcess] Restoring 4 unacknowledged message(s).
(env1)ubuntu@ip-172-31-22-65:~/projects/tp$ celery -A tp purge
WARNING: This will remove all tasks from queue: celery.
There is no undo for this operation!
(to skip this prompt use the -f option)
Are you sure you want to delete all tasks (yes/NO)? yes
Purged 81 messages from 1 known task queue.
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如何从命令行获取排队项的列表?
itz*_*nTV 18
如果您想获得所有计划任务,
celery inspect scheduled
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查找所有活动队列
celery inspect active_queues
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对于状态
celery inspect stats
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对于所有命令
celery inspect
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如果你想明确地得到它.因为你正在使用redis
队列.然后
redis-cli
>KEYS * #find all keys
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然后找出与之相关的东西 celery
>LLEN KEY # i think it gives length of list
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这是Redis的复制粘贴解决方案:
def get_celery_queue_len(queue_name):
from yourproject.celery import app as celery_app
with celery_app.pool.acquire(block=True) as conn:
return conn.default_channel.client.llen(queue_name)
def get_celery_queue_items(queue_name):
import base64
import json
from yourproject.celery import app as celery_app
with celery_app.pool.acquire(block=True) as conn:
tasks = conn.default_channel.client.lrange(queue_name, 0, -1)
decoded_tasks = []
for task in tasks:
j = json.loads(task)
body = json.loads(base64.b64decode(j['body']))
decoded_tasks.append(body)
return decoded_tasks
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它适用于Django。只是不要忘记改变yourproject.celery
。
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