Łuk*_*ski 8 java spring jpa intellij-idea spring-data-jpa
现在我正在设置REST api模板.我想使用弹簧启动与弹簧数据集成,一切都很好,但我想利用Intellij 14 spring数据插件的优势,并启用自动完成ie findByFirstName(...).我尝试在这个intelij 11演示中实现类似的东西http://blog.jetbrains.com/idea/2011/11/enjoy-spring-data-jpa-in-intellij-11/
如何在现有项目中启用spring数据插件?
我目前的配置

@SpringBootApplication
public class Application {
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
}
@Configuration
@EnableTransactionManagement
@EnableJpaRepositories("com.test.repository")
public class TestDataBaseConfiguration {
@Bean
public DataSource dataSource() {
return new EmbeddedDatabaseBuilder().setType(EmbeddedDatabaseType.H2).build();
}
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
LocalContainerEntityManagerFactoryBean entityManagerFactoryBean = new LocalContainerEntityManagerFactoryBean();
entityManagerFactoryBean.setDataSource(dataSource());
entityManagerFactoryBean.setJpaVendorAdapter(new HibernateJpaVendorAdapter());
entityManagerFactoryBean.setPackagesToScan("com.test.entities");
entityManagerFactoryBean.setJpaProperties(jpaProperties());
return entityManagerFactoryBean;
}
private Properties jpaProperties() {
Properties properties = new Properties();
properties.setProperty("hibernate.hbm2ddl.auto", "create-drop");
properties.setProperty("hibernate.dialect", "org.hibernate.dialect.H2Dialect");
properties.setProperty("hibernate.show_sql", "false");
properties.setProperty("hibernate.format_sql", "false");
return properties;
}
@Bean
public JpaTransactionManager transactionManager() {
JpaTransactionManager transactionManager = new JpaTransactionManager();
transactionManager.setEntityManagerFactory(entityManagerFactory().getObject());
transactionManager.setDataSource(dataSource());
return transactionManager;
}
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
1146 次 |
| 最近记录: |