csf*_*csf 2 jpa criteria java-ee
这是mycode:
public List<Veiculo> getAll()
{
CriteriaQuery<Veiculo> criteria = this.entityManager
.getCriteriaBuilder().createQuery(Veiculo.class);
return this.entityManager.createQuery(
criteria.select(criteria.from(Veiculo.class))).getResultList();
}
Run Code Online (Sandbox Code Playgroud)
现在,我需要一个用于条件查询的order by子句。
orderby veiculo.getServico
Run Code Online (Sandbox Code Playgroud)
我尝试,但是不工作
public List<Veiculo> getAll()
{
CriteriaQuery<Veiculo> criteria = this.entityManager
.getCriteriaBuilder().createQuery(Veiculo.class);
return this.entityManager.createQuery(
criteria.select(criteria.from(Veiculo.class)).orderBy(getVeiculo().getServico())).getResultList();
}
Run Code Online (Sandbox Code Playgroud)
重写后的内容应该对您有用,没有编译,因此请考虑作为示例性的元代码
CriteriaBuilder cb = this.entityManager
.getCriteriaBuilder();
CriteriaQuery<Veiculo> criteria = cb.createQuery(Veiculo.class);
Root<Veiculo> root = criteria.from(Veiculo.class);
return this.entityManager.createQuery(
criteria.select(root).orderBy(cb.asc(root.get("servico"))))
.getResultList();
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2392 次 |
| 最近记录: |