ar2*_*015 1 c++ printf string-formatting c++11
如何将此代码从C转换为C++?
char out[61]; //null terminator
for (i = 0; i < 20; i++) {
snprintf(out+i*3, 4, "%02x ", obuf[i])
}
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我找不到任何替代方案snprintf.
使用stringstream来自的课程<sstream>.
例如:
#include <iostream>
#include <iomanip>
#include <sstream>
#include <string>
using namespace std;
int main()
{
stringstream ss;
for (int i = 0; i < 20; i++) {
ss << setw(3) << i;
}
cout << "Resulting string: " << endl;
cout << ss.str() << endl;
printf("Resulting char*: \n%s\n", ss.str().c_str() );
return 0;
}
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