使用干净的URL在yii2中的超链接中传递多个参数,Html :: a()不会生成干净的URL

Question

我想通过生成中提到的方法中的超链接 http://www.yiiframework.com/doc-2.0/guide-helper-html.html#hyperlinks这样

 Html::a('<b>Register</b>', 
    ['story/create', array('id' =>39,'usr'=>'11')], 
    ['class' => 'profile-link'])

我想得到网址 story/create/id/39/usr/11

但它正在产生

story/create?1%5Bid%5D=39&1%5Busr%5D=1

我启用了yii2的干净网址功能

  'urlManager' => [
        'class' => 'yii\web\UrlManager',
        // Disable index.php
        'showScriptName' => false,
        // Disable r= routes
        'enablePrettyUrl' => true,
        'rules' => array(
                '<controller:\w+>/<id:\d+>' => '<controller>/view',
                '<controller:\w+>/<action:\w+>/<id:\d+>' => '<controller>/<action>',
                '<controller:\w+>/<action:\w+>' => '<controller>/<action>',
        ),
        ], also.

如何实现这一目标？

Answer 1

随着生成url使用(见更多http://www.yiiframework.com/doc-2.0/guide-helper-url.html):

Html::a('<b>Register</b>', 
        ['story/create', 'id' =>39,'usr'=>'11'], 
        ['class' => 'profile-link'])

在urlManager中输入新规则:

rules' => array(
  ....
  'story/create/<id:\d+>/<usr:\d+>' => 'story/create',

        ),

输出网址将是这样的:

story/create/39/11

在控制器中:

public function actionCreate($id, $usr)

并且Yii2提供此参数.