调用web api时C#不支持的授权类型

Question

我正在尝试从ac#WPF桌面应用程序执行发布到我的WebAPI.

无论我做什么,我都会

{ "错误": "unsupported_grant_type"}

这就是我尝试过的(我已经尝试过所有可以找到的东西):

此外,dev web api目前正在进行测试:http://studiodev.biz/

基本http客户端对象:

var client = new HttpClient()
client.BaseAddress = new Uri("http://studiodev.biz/");
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("text/plain"));
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("*/*"));

使用以下发送方法:

var response = await client.PostAsJsonAsync("token", "{'grant_type'='password'&'username'='username'&'password'='password'");
var response = await client.PostAsJsonAsync("token", "grant_type=password&username=username&password=password");

在那次失败后,我做了一些谷歌搜索并尝试:

LoginModel data = new LoginModel(username, password);
string json = JsonConvert.SerializeObject(data);
await client.PostAsync("token", new JsonContent(json));

同样的结果,所以我试过:

req.Content = new StringContent(json, Encoding.UTF8, "application/x-www-form-urlencoded");
await client.SendAsync(req).ContinueWith(respTask =>
{
 Application.Current.Dispatcher.Invoke(new Action(() => { label.Content = respTask.Result.ToString(); }));
});

注意:我可以通过Chrome成功拨打电话.

更新Fiddler结果

请有人帮我成功拨打上述网页API ...如果我能帮忙澄清,请告诉我.谢谢!!

Answer 1

默认实现OAuthAuthorizationServerHandler只接受表单编码(即application/x-www-form-urlencoded)而不是JSON编码(application/JSON).

您的请求ContentType应该是application/x-www-form-urlencoded并将正文中的数据传递为:

grant_type=password&username=Alice&password=password123

即不是JSON格式.

上面的chrome示例有效,因为它没有将数据作为JSON传递.你只需要这个来获得一个令牌; 对于API的其他方法,您可以使用JSON.

这里也讨论了这种问题.

Answer 2

1)注意URL:"localhost:55828/token"(不是"localhost:55828/API/token")

2)记下请求数据.它不是json格式,它只是没有双引号的普通数据."userName=xxx@gmail.com&password=Test123$&grant_type=password"

3)注意内容类型.内容类型:'application/x-www-form-urlencoded'(不是Content-Type:'application/json')

4)当您使用javascript发布帖子请求时,您可以使用以下内容:

$http.post("localhost:55828/token", 
    "userName=" + encodeURIComponent(email) +
        "&password=" + encodeURIComponent(password) +
        "&grant_type=password",
    {headers: { 'Content-Type': 'application/x-www-form-urlencoded' }}
).success(function (data) {//...

请参阅Postman下面的截图:

Answer 3

这是一个工作示例,我曾经使用SSL在端口43305上运行我的本地Web API应用程序的请求.我也把这个项目放在了GitHub上. https://github.com/casmer/WebAPI-getauthtoken

using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using Newtonsoft.Json;
using System.Net.Http;
using System.Web;

namespace GetAccessTokenSample
{
  class Program
  {
    private static string baseUrl = "https://localhost:44305";

    static void Main(string[] args)
    {

      Console.WriteLine("Enter Username: ");
      string username= Console.ReadLine();
      Console.WriteLine("Enter Password: ");
      string password = Console.ReadLine();

      LoginTokenResult accessToken = GetLoginToken(username,password);
      if (accessToken.AccessToken != null)
      {
        Console.WriteLine(accessToken);
      }
      else
      {
        Console.WriteLine("Error Occurred:{0}, {1}", accessToken.Error, accessToken.ErrorDescription);
      }

    }


    private static LoginTokenResult GetLoginToken(string username, string password)
    {

      HttpClient client = new HttpClient();
      client.BaseAddress = new Uri(baseUrl);
      //TokenRequestViewModel tokenRequest = new TokenRequestViewModel() { 
      //password=userInfo.Password, username=userInfo.UserName};
      HttpResponseMessage response =
        client.PostAsync("Token",
          new StringContent(string.Format("grant_type=password&username={0}&password={1}",
            HttpUtility.UrlEncode(username),
            HttpUtility.UrlEncode(password)), Encoding.UTF8,
            "application/x-www-form-urlencoded")).Result;

      string resultJSON = response.Content.ReadAsStringAsync().Result;
      LoginTokenResult result = JsonConvert.DeserializeObject<LoginTokenResult>(resultJSON);

      return result;
    }

    public class LoginTokenResult
    {
      public override string ToString()
      {
        return AccessToken;
      }

      [JsonProperty(PropertyName = "access_token")]
      public string AccessToken { get; set; }

      [JsonProperty(PropertyName = "error")]
      public string Error { get; set; }

      [JsonProperty(PropertyName = "error_description")]
      public string ErrorDescription { get; set; }

    }

  }
}

Answer 4

如果您使用的是RestSharp,则需要按以下方式发出请求:

public static U PostLogin<U>(string url, Authentication obj)
            where U : new()
        {
            RestClient client = new RestClient();
            client.BaseUrl = new Uri(host + url);
            var request = new RestRequest(Method.POST);
            string encodedBody = string.Format("grant_type=password&username={0}&password={1}",
                obj.username,obj.password);
            request.AddParameter("application/x-www-form-urlencoded", encodedBody, ParameterType.RequestBody);
            request.AddParameter("Content-Type", "application/x-www-form-urlencoded", ParameterType.HttpHeader);
            var response = client.Execute<U>(request);

             return response.Data;

        }