Kon*_*tyn 4 python document docx paragraphs
我有 .docx 文件,其中包含许多段落和表格,例如:
标准杆2
2.1 标准杆 21
我需要迭代所有对象并制作字典,可能是 json 格式,如:
{par1: [table1, table2, table3], par2[table1,table2, {par21: [table1,table2]} ] }
从 docx.api 导入文件
文件名 = 'test.docx'
文档 = 文档(docx=文件名)
对于 document.tables 中的表格:
打印表
对于 document.paragraphs 中的段落:
打印段落文本
我如何关联每个段落和表格?
你能提出一些建议吗?
小智 6
from docx import Document
from docx.document import Document as _Document
from docx.oxml.text.paragraph import CT_P
from docx.oxml.table import CT_Tbl
from docx.table import _Cell, Table
from docx.text.paragraph import Paragraph
def iter_block_items(parent):
"""
Generate a reference to each paragraph and table child within *parent*,
in document order. Each returned value is an instance of either Table or
Paragraph. *parent* would most commonly be a reference to a main
Document object, but also works for a _Cell object, which itself can
contain paragraphs and tables.
"""
if isinstance(parent, _Document):
parent_elm = parent.element.body
elif isinstance(parent, _Cell):
parent_elm = parent._tc
elif isinstance(parent, _Row):
parent_elm = parent._tr
else:
raise ValueError("something's not right")
for child in parent_elm.iterchildren():
if isinstance(child, CT_P):
yield Paragraph(child, parent)
elif isinstance(child, CT_Tbl):
yield Table(child, parent)
document = Document('test.docx')
for block in iter_block_items(document):
#print(block.text if isinstance(block, Paragraph) else '<table>')
if isinstance(block, Paragraph):
print(block.text)
elif isinstance(block, Table):
for row in block.rows:
row_data = []
for cell in row.cells:
for paragraph in cell.paragraphs:
row_data.append(paragraph.text)
print("\t".join(row_data))
Run Code Online (Sandbox Code Playgroud)
python-docx 库上还没有实现这样的方法,但有一种解决方法可以按照它们出现的顺序迭代 docx 的所有元素:https ://github.com/python-openxml/python-docx /问题/40
您可以尝试迭代所有这些,并检查该对象是否是表或段落的实例,并以此为基础建立您的逻辑。
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