RabbitMQ 3.5和消息优先级

Omm*_*mit 6 c# rabbitmq

RabbitMQ 3.5现在支持消息优先级 ; 但是,我无法建立一个有效的例子.我把我的代码放在下面.它包括我期望的输出和实际的输出.我会对更多文档和/或工作示例感兴趣.

所以我的问题很简单:如何在Rabbit 3.5.0.0中使用消息优先级?

出版商:

using System;
using RabbitMQ.Client;
using System.Text;
using System.Collections.Generic;

class Publisher
{

    public static void Main()
    {
        var factory = new ConnectionFactory() { HostName = "localhost" };
        using (var connection = factory.CreateConnection())
        {
            using (var channel = connection.CreateModel())
            {
                IDictionary <String , Object> args = new Dictionary<String,Object>() ;
                args.Add(" x-max-priority ", 10);
                channel.QueueDeclare("task_queue1", true, false, true, args);

                for (int i = 1 ; i<=10; i++ )
                {
                    var message = "Message";
                    var body = Encoding.UTF8.GetBytes(message + " " + i);
                    var properties = channel.CreateBasicProperties();
                    properties.SetPersistent(true);
                    properties.Priority = Convert.ToByte(i);
                    channel.BasicPublish("", "task_queue1", properties, body);
                }
            }
        }
    }
}
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消费者:

using System;
using RabbitMQ.Client;
using RabbitMQ.Client.Events;
using System.Text;
using System.Threading;
using System.Collections.Generic;

namespace Consumer
{ 
    class Worker
    {
        public static void Main()
        {
            var factory = new ConnectionFactory() { HostName = "localhost" };
            using (var connection = factory.CreateConnection())
            {
                using (var channel = connection.CreateModel())
                {
                    IDictionary<String, Object> args = new Dictionary<String, Object>();                      
                    channel.BasicQos(0, 1, false);
                    var consumer = new QueueingBasicConsumer(channel);
                    IDictionary<string, object> consumerArgs = new Dictionary<string, object>();
                    channel.BasicConsume( "task_queue1", false, "", args, consumer);
                    Console.WriteLine(" [*] Waiting for messages. " +
                                      "To exit press CTRL+C");
                    while (true)
                    {
                        var ea = (BasicDeliverEventArgs)consumer.Queue.Dequeue();
                        var body = ea.Body;
                        var message = Encoding.UTF8.GetString(body);
                        Console.WriteLine(" [x] Received {0}", message);
                        channel.BasicAck(ea.DeliveryTag, false);
                    }
                }
            }
        }
    }
}
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实际产量:

[*] Waiting for messages. To exit press CTRL+C
[x] Received Message 1
[x] Received Message 2
[x] Received Message 3
[x] Received Message 4
[x] Received Message 5
[x] Received Message 6
[x] Received Message 7
[x] Received Message 8
[x] Received Message 9
[x] Received Message 10
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预期产量:

[*] Waiting for messages. To exit press CTRL+C
[x] Received Message 10
[x] Received Message 9
[x] Received Message 8
[x] Received Message 7
[x] Received Message 6
[x] Received Message 5
[x] Received Message 4
[x] Received Message 3
[x] Received Message 2
[x] Received Message 1
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更新#1.我发现一个例子在Java中这里.然而,它是Rabbit 3.4.xx插件,并入3.5.我能看到的唯一区别是它们将优先级表示为int而我的是一个字节.但我觉得那是一个红鲱鱼.我在这里有点不知所措.

Omm*_*mit 8

好吧,我解决了.这是一个愚蠢的错误.我写:

args.Add(" x-max-priority ", 10);
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它应该是

args.Add("x-max-priority", 10);
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我会把它留下来,以便其他人可以在C#中有一个Rabbitmq 3.5的优先级队列的工作示例.