Slick 3.0多对多查询,将join作为可迭代

jbr*_*own 7 scala slick slick-3.0

我使用Slick 3.0创建了一个多对多的集合,但我正在努力以我想要的方式检索数据.

事件和兴趣之间存在多对多关系.这是我的表格:

case class EventDao(title: String,
                    id: Option[Int] = None)


class EventsTable(tag: Tag)
  extends Table[EventDao](tag, "events") {

  def id = column[Int]("event_id", O.PrimaryKey, O.AutoInc)
  def title = column[String]("title")

  def * = (
    title,
    id.?) <> (EventDao.tupled, EventDao.unapply)

  def interests = EventInterestQueries.query.filter(_.eventId === id)
    .flatMap(_.interestFk)
}


object EventQueries {

  lazy val query = TableQuery[EventsTable]

  val findById = Compiled { k: Rep[Int] =>
    query.filter(_.id === k)
  }
}
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这是活动兴趣:

case class EventInterestDao(event: Int, interest: Int)


class EventsInterestsTable(tag: Tag)
  extends Table[EventInterestDao](tag, "events_interests") {

  def eventId = column[Int]("event_id")
  def interestId = column[Int]("interest_id")

  def * = (
    eventId,
    interestId) <> (EventInterestDao.tupled, EventInterestDao.unapply)

  def eventFk = foreignKey("event_fk", eventId, EventQueries.query)(e => e.id)
  def interestFk = foreignKey("interest_fk", interestId, InterestQueries.query)(i => i.id)
}


object EventInterestQueries {
  lazy val query = TableQuery[EventsInterestsTable]
}
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最后的兴趣:

case class InterestDao(name: String,
                       id: Option[Int] = None)

class InterestsTable(tag: Tag)
  extends Table[InterestDao](tag, "interests") {

  def id = column[Int]("interest_id", O.PrimaryKey, O.AutoInc)
  def name = column[String]("name")
  def name_idx = index("idx_name", name, unique = true)

  def * = (
    name,
    id.?) <> (InterestDao.tupled, InterestDao.unapply)

  def events = EventInterestQueries.query.filter(_.interestId === id)
    .flatMap(_.eventFk)
}


object InterestQueries {

  lazy val query = TableQuery[InterestsTable]

  val findById = Compiled { k: Rep[Int] =>
    query.filter(_.id === k)
  }
}
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我可以使用以下命令查询和检索(event.name,interest)的元组:

val eventInterestQuery = for {
  event <- EventQueries.query
  interest <- event.interests
} yield (event.title, interest.name)

Await.result(db.run(eventInterestQuery.result).map(println), Duration.Inf)
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所以这就是我现在拥有的.

我想要的是能够填充案例类,如:

case class EventDao(title: String,
                interests: Seq[InterestDao],
                id: Option[Int] = None)
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麻烦的是,如果我像这样更新我的案例类,它会弄乱我的def *投射EventsTable.另外,我必须将EventsTable.interests过滤器重命名EventsTable.interestIds为有点丑陋的东西,但如果有必要,我可以忍受.

此外,我找不到一种编写产生的for查询的方法(event.name, Seq(interest.name)).无论如何,这只是我的一个垫脚石,能够产生一个(EventDao, Seq(InterestDao))我真正想要回归的元组.

有谁知道我怎么能做到这些事情?我也希望能够"获取"一定数量的兴趣,因此对于某些查询,所有内容都将被退回,但对于其他查询,只有前三个会被退回.

jbr*_*own 6

所以看完这个页面并在邮件列表上聊天后,我终于明白了:

val eventInterestQuery = for {
  event <- EventQueries.query
  interest <- event.interests
} yield (event, interest)

Await.result(db.run(eventInterestQuery.result
  // convert the interests to a sequence.
  .map {
  _.groupBy(_._1)
    .map {
      case (k,v) => (k, v.map(_._2))
  }.toSeq
}
), Duration.Inf)
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  • 那是疯了,你被迫将*整个未分组的结果集*发送到线路*然后*组在客户端上.对于小的结果集,当然,没什么大不了的,但是发送100K +记录可以轻松地在数据库级别进行分组,哇. (8认同)